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# A qualified worker digs a well in 5 hours. He invites 2 appr

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A qualified worker digs a well in 5 hours. He invites 2 appr [#permalink]

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04 Oct 2006, 08:14
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Question Stats:

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A qualified worker digs a well in 5 hours. He invites 2 apprentices, both capable of working 3/4 as fast and 2 trainees both working 1/5 as fast as he. If the five-person team digs the same well, how much time does the team need to finish the job?

A. 1:24
B. 1:34
C. 1:44
D. 1:54
E. 2:14
[Reveal] Spoiler: OA

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04 Oct 2006, 10:24
Q rate/day = 1/5
A=(3/4)(1/5)=(3/20)(2)=3/10
T=(1/5)(1/5)=(1/25)(2)=1/50

t(1/5+3/10+1/50)=1 = 29/50 â€“-> t= 50/29
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04 Oct 2006, 14:34
X & Y wrote:
Q rate/day = 1/5
A=(3/4)(1/5)=(3/20)(2)=3/10
T=(1/5)(1/5)=(1/25)(2)=1/50

t(1/5+3/10+1/50)=1 = 29/50 â€“-> t= 50/29

I think it must be 2/25 instead of 1/50.
The explanation is valid though.

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04 Oct 2006, 14:44
anandsebastin wrote:
X & Y wrote:
Q rate/day = 1/5
A=(3/4)(1/5)=(3/20)(2)=3/10
T=(1/5)(1/5)=(1/25)(2)=1/50

t(1/5+3/10+1/50)=1 = 29/50 â€“-> t= 50/29

I think it must be 2/25 instead of 1/50.
The explanation is valid though.

You are right; since I did it on paper and then copied to the computer I missed that. Thanks..

It is 2/25
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05 Oct 2006, 01:33
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I have another way.

A can do a work in 5 hours.

Now 2 persons whose efficiency is 3/4 of A joins him.
ie 1 person whose efficiency is 2x3/4 ie 3/2 times of A joins him.

Again 2 persons whose efficiency is 1/5 of A joins him.
ie 1 person whose efficiency is 2x1/5 ie 2/5 times of A joins him.

So finally the people involved in the work is
A+ 3/2(A) + 2/5(A)
ie 29/10 (A)

Since A alone takes 5 hours
29/10 (A) will take 10/29 x 5 i.e 50 /29 hours
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14 Jun 2007, 15:48
Q rate/day = 1/5
A=(3/4)(1/5)=(3/20)(2)=3/10
T=(1/5)(1/5)=(1/25)(2)=2/25

t(1/5+3/10+2/25)=1 = 29/50 --> t= 50/29 or 1:40
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01 Jul 2007, 11:57
I must be totally blind! I do not see how you can get 1.4 hours out of 50/29.

Here's how I see it: each hour 29/50 of the job is completed, therefore after the first hour, 29/50 is complete and 21/50 is still remaining to be completed. 21/50 is just slightly less than 29/50, which is inline with the 1.7 that Juaz got.

Can someone please explain what I am missing?

Thanks!

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01 Jul 2007, 12:11
Bluebird wrote:
I must be totally blind! I do not see how you can get 1.4 hours out of 50/29.

Here's how I see it: each hour 29/50 of the job is completed, therefore after the first hour, 29/50 is complete and 21/50 is still remaining to be completed. 21/50 is just slightly less than 29/50, which is inline with the 1.7 that Juaz got.

Can someone please explain what I am missing?

Thanks!

50/29 = 1.7 hrs

(.7)60 = approx 40 mins

so total time = 1 hour and 40 mins.

I think the answers are a bit confusing.

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Re: GMAT Club Test M00 [#permalink]

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23 May 2008, 00:03
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lucyqin wrote:
chengliu wrote:
Hey guys can someone please explain to me the explanation below?? Its late and i just dont understand how 50/29 = 1:44 ???

A qualified worker digs a well in 5 hours. He invites 2 apprentices, both capable of working 3/4 as fast and 2 trainees both working 1/5 as fast as he. If the five-person team digs the same well, how much time does the team need to finish the job?

* 1:24
* 1:34
* 1:44
* 1:54
* 2:14

R= 1/5 + 2*(3/4)*(1/5)+2*(1/5)*(1/5)= 58/100
T=100/58 or 50/29

So, T= 50/29 or 1:44.

The unit for T is in hours. T=50/29 means 1 hour and 21/29 of an hour which equals 44 minutes.

Is there a fast way of calculating the time 44 mims from 21/29 hours ??

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Re: GMAT Club Test M00 [#permalink]

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23 May 2008, 00:55
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Expert's post
21/29 is slightly greater (~1/30) than 21/30 or 42/60 or 42 mins.
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Re: GMAT Club Test M00 [#permalink]

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15 Feb 2013, 03:20
bunuel,
Is there a method( text book approach) to calculate the time 44 mims from 21/29 hours ??
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Re: GMAT Club Test M00 [#permalink]

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15 Feb 2013, 03:32
Sachin9 wrote:
bunuel,
Is there a method( text book approach) to calculate the time 44 mims from 21/29 hours ??

21/29 th of an hour is (21/29) * (60 minutes) = ~43 minutes.

Walker gave perfect way to get approximate result here: gmat-club-test-m00-64356.html#p470808
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Re: A qualified worker digs a well in 5 hours. He invites 2 appr [#permalink]

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05 Oct 2013, 02:36
Stiv wrote:
A qualified worker digs a well in 5 hours. He invites 2 apprentices, both capable of working 3/4 as fast and 2 trainees both working 1/5 as fast as he. If the five-person team digs the same well, how much time does the team need to finish the job?
A 1:24
B 1:34
C 1:44
D 1:54
E 2:14

Your question sounds vague to me. The answer should be in terms of time. Anyway I just solved based on the data given.

Rate of the Work = $$1 / 5$$

Rate of 2 apprentice = $$2 * (1/5) * (3/4) = 6/20$$

Rate of 2 Trainees = $$2 * (1/5) * (1/5) = 2/25$$

Total Rate of 5 people = $$(1/5) + (6/20) + (2/25) = 58/100$$

Time required to dig 1 Well = $$1/ (58/100) = 100/58 hours$$
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Re: A qualified worker digs a well in 5 hours. He invites 2 appr [#permalink]

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05 Oct 2013, 02:57
Actually question is asking about the time they need. options are in hours:minutes.
Question is ok.

and answer is correct as you have calculated : 100/58 hrs that is 1.72 hrs - 1 hr and 44 minutes, so 1:44, hence, C.

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Re: A qualified worker digs a well in 5 hours. He invites 2 appr [#permalink]

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05 Oct 2013, 03:18
Chiranjeevee wrote:
Actually question is asking about the time they need. options are in hours:minutes.
Question is ok.

and answer is correct as you have calculated : 100/58 hrs that is 1.72 hrs - 1 hr and 44 minutes, so 1:44, hence, C.

Thanks for the info. I better get used to this type of time representation.
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Re: A qualified worker digs a well in 5 hours. He invites 2 appr [#permalink]

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17 Oct 2013, 12:30
Q rate = 1/5
A rate = 1/5*3/4
T rate = 1/5*1/5

1/5+2*(1/5*3/4)+2*(1/5*1/5)=1/t

1/5+6/20+2/25=1/t

58/100=1/t

58t=100

t=100/58=1 21/29, which is slightly below 1 3/4, so it must be 1:44 for an answer

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Work/rate problem - was my approach incorrect? [#permalink]

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02 Nov 2013, 21:57
A qualified worker digs a well in 5 hours. He invites 2 apprentices, both capable of working 3/4 as fast and 2 trainees both working 1/5 as fast as he. If the five-person team digs the same well, how much time does the team need to finish the job?

A) 1:24
B) 1:34
C) 1:44
D) 1:54
E) 2:14

I started with the original rate for the worker as 1/5.

Each apprentice would have a rate (1/5)*(3/4) = 3/20

Each trainee would have a rate (1/5) * (1/5) = 1/25

Combining all of it together 1/5 + 3/20 + 3/20 + 1/25 + 1/25 = 58/100 per hour

After one hour, the remaining work to be done is 42/100

Is it possible to use this approach to solve the problem?

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Re: Work/rate problem - was my approach incorrect? [#permalink]

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03 Nov 2013, 04:30
undecidedonmba wrote:
A qualified worker digs a well in 5 hours. He invites 2 apprentices, both capable of working 3/4 as fast and 2 trainees both working 1/5 as fast as he. If the five-person team digs the same well, how much time does the team need to finish the job?

A) 1:24
B) 1:34
C) 1:44
D) 1:54
E) 2:14

I started with the original rate for the worker as 1/5.

Each apprentice would have a rate (1/5)*(3/4) = 3/20

Each trainee would have a rate (1/5) * (1/5) = 1/25

Combining all of it together 1/5 + 3/20 + 3/20 + 1/25 + 1/25 = 58/100 per hour

After one hour, the remaining work to be done is 42/100

Is it possible to use this approach to solve the problem?

Hi,

Your approach is perfectly correct but I do not see the answer options to be in sync with the question that's asked. The question is "hpw much time does the team need to finish the job" but answer options are in proportion/ratio format. Can you verify whether the question stem is correct?
According to me the answer should be 50/29 hours. I used the same approach as yours.
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Re: GMAT Club Test M00 [#permalink]

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Re: A qualified worker digs a well in 5 hours. He invites 2 appr [#permalink]

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19 Oct 2015, 09:28
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Re: A qualified worker digs a well in 5 hours. He invites 2 appr   [#permalink] 19 Oct 2015, 09:28

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