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A rectangular box is 10 inches wide, 10 inches long, and 5

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Intern
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A rectangular box is 10 inches wide, 10 inches long, and 5 [#permalink]

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New post 20 Apr 2005, 11:32
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A rectangular box is 10 inches wide, 10 inches long, and 5 inches high. What is the greatest possible (straight-line) distance, in inches, between any two points on the box?

1) 15
2) 20
3) 25
4) 10 * square root 2
5) 10 * square root 3

Is there an equation to figure this out?

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Director
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New post 20 Apr 2005, 11:38
Ans is A


Diagonal is the longest distance in a rectangular box.

Diagonal D = sqrt (L^2 + W^2 + H^2)

D = sqrt (10^2 + 10^2 + 5^2)
D = sqrt (225)
D = 15.

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New post 20 Apr 2005, 11:51
well, my reasoning below leads me to 15.
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New post 20 Apr 2005, 13:59
thearch wrote:
well, my reasoning below leads me to 15.


nice and clear drawing

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Senior Manager
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New post 07 Dec 2005, 07:22
This is an old post, but I just wanted to make sure everyone knew the quick and easy formula:

Take 10^2+10^2+5^2
We get 100+100+25 = 225
Take the square root of this to get 15.

No geometry or equations needed.

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New post 07 Dec 2005, 13:23
The longest rot that can fit into a rectangular box=sq rt. l^2+w^2+h^2= sqrt.10^2+10^2+5^2=sqrt 222=15

A stands
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  [#permalink] 07 Dec 2005, 13:23
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A rectangular box is 10 inches wide, 10 inches long, and 5

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