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A rectangular box is 10 inches wide, 10 inches long, and 5 inches high

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Math Expert
Joined: 02 Sep 2009
Posts: 43335

Kudos [?]: 139513 [0], given: 12794

A rectangular box is 10 inches wide, 10 inches long, and 5 inches high [#permalink]

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06 Dec 2017, 03:21
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Difficulty:

15% (low)

Question Stats:

78% (00:41) correct 22% (00:09) wrong based on 35 sessions

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A rectangular box is 10 inches wide, 10 inches long, and 5 inches high. What is the greatest possible (straight-line) distance, in inches, between any two points on the box?

(A) 15
(B) 20
(C) 25
(D) 10√2
(E) 10√3
[Reveal] Spoiler: OA

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Kudos [?]: 139513 [0], given: 12794

Intern
Joined: 30 Sep 2017
Posts: 11

Kudos [?]: 2 [0], given: 0

Re: A rectangular box is 10 inches wide, 10 inches long, and 5 inches high [#permalink]

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06 Dec 2017, 03:37
We can use super Pythagoras theorem here:

l^2+b^2+w^2
100+100+25
225
√225

A. 15

Sent from my ONEPLUS A3003 using GMAT Club Forum mobile app

Kudos [?]: 2 [0], given: 0

Director
Joined: 18 Aug 2016
Posts: 627

Kudos [?]: 208 [0], given: 166

Concentration: Strategy, Technology
GMAT 1: 630 Q47 V29
GMAT 2: 740 Q51 V38
Re: A rectangular box is 10 inches wide, 10 inches long, and 5 inches high [#permalink]

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06 Dec 2017, 03:47
Bunuel wrote:
A rectangular box is 10 inches wide, 10 inches long, and 5 inches high. What is the greatest possible (straight-line) distance, in inches, between any two points on the box?

(A) 15
(B) 20
(C) 25
(D) 10√2
(E) 10√3

$$Diagnoal of Cube = \sqrt{l^2 + b^2 + h^2}$$
$$\sqrt{100 + 100 + 25}$$
15
A
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Luckisnoexcuse

Kudos [?]: 208 [0], given: 166

Senior Manager
Joined: 15 Jan 2017
Posts: 360

Kudos [?]: 8 [0], given: 830

Re: A rectangular box is 10 inches wide, 10 inches long, and 5 inches high [#permalink]

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12 Dec 2017, 14:36
What level question would this be?

Kudos [?]: 8 [0], given: 830

Re: A rectangular box is 10 inches wide, 10 inches long, and 5 inches high   [#permalink] 12 Dec 2017, 14:36
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