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A restaurant offers a $10meal that consists of exactly three food ite
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28 Jun 2019, 18:12
Question Stats:
15% (01:45) correct 85% (01:27) wrong based on 39 sessions
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A restaurant offers a $10meal that consists of exactly three food items out of: Burger, Sandwich, Pizza, French Fries, Coke If Andy has to buy either a coke or a burger, in how many ways can he select his meal? A. 3 B. 6 C. 9 D. 10 E. 12
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Re: A restaurant offers a $10meal that consists of exactly three food ite
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29 Jun 2019, 04:53
N22J wrote: A restaurant offers a $10meal that consists of exactly three food items out of: Burger, Sandwich, Pizza, French Fries, Coke If Andy has to buy either a coke or a burger, in how many ways can he select his meal? A. 3 B. 6 C. 9 D. 10 E. 12
Posted from my mobile device Since Andy has to buy a coke or a burger => gives us 2 choices and we have to chose 2 out of 3 meals for $10 meal which can be done in 3C2 = 3 ways this gives us cases BSP, BSF, BPF, CSP, CSF, CPF. There are total 6 cases. IMO B 6 should be correct.
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Re: A restaurant offers a $10meal that consists of exactly three food ite
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29 Jun 2019, 05:18
Actually you have one more choice of having both as well, so 3 more combinations
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Re: A restaurant offers a $10meal that consists of exactly three food ite
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29 Jun 2019, 05:21
N22J wrote: Actually you have one more choice of having both as well, so 3 more combinations
Posted from my mobile device Andy has to buy either a coke or a burger means he can choose 1 out of the 2 not both. Is it correct?
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Re: A restaurant offers a $10meal that consists of exactly three food ite
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29 Jun 2019, 05:23
But the question says either or right? Which shoul mean only one out of the two right?
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Re: A restaurant offers a $10meal that consists of exactly three food ite
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29 Jun 2019, 06:27
If there were no restrictions at all, he'd be able to choose 5C3 = 5*4*3/3! = 10 different meals. The only one of these meals that doesn't include a burger or a coke is {pizza, fries, sandwich}. That leaves us with 10  1 = 9 meals that do include a burger or a coke (or both). As the question is worded, I would not interpret the "or" as an "exclusive or", though I agree the question should be clearer about that. If you do assume that he can only buy one of the two foods (burger or coke, but not both), the answer is 6.
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Re: A restaurant offers a $10meal that consists of exactly three food ite
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29 Jun 2019, 07:24
N22J wrote: A restaurant offers a $10meal that consists of exactly three food items out of: Burger, Sandwich, Pizza, French Fries, Coke If Andy has to buy either a coke or a burger, in how many ways can he select his meal? A. 3 B. 6 C. 9 D. 10 E. 12
Posted from my mobile device Assuming the either a coke or a burger in mean implies he can select only a burger or a coke out of the two= 2C1 Selecting remaining 2 food items out of Sandwich, Pizza, French Fries= 3C2 Therefore,number of ways in which he can select his mean=3C2*2C1= 6 Hope it helps!!



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Re: A restaurant offers a $10meal that consists of exactly three food ite
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29 Jun 2019, 07:37
Try this to understand "Either or"
From 1 to 50, how many numbers are divisible by either 2 or 5?
Will you count 10, 20,...or not?
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Re: A restaurant offers a $10meal that consists of exactly three food ite
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29 Jun 2019, 07:38
Try this to understand "Either or"
From 1 to 50, how many numbers are divisible by either 2 or 5?
Will you count 10, 20,...or not?



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Re: A restaurant offers a $10meal that consists of exactly three food ite
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29 Jun 2019, 07:48
N22J wrote: Try this to understand "Either or"
From 1 to 50, how many numbers are divisible by either 2 or 5?
Will you count 10, 20,...or not? Numbers divisible by 2 = (502)/2 + 1 = 25 Numbers divisible by 5= (505)/5 + 1 = 10 Numbers divisible by both 2 and 5 =ones divisible by 10= 5 So numbers are divisible by either 2 or 5 = 25+105 = 30Here either or..means div by 2 + div by 5  Not divisible by both




Re: A restaurant offers a $10meal that consists of exactly three food ite
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29 Jun 2019, 07:48






