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Re: A right cylindrical container with radius 2 meters and height 1 meter [#permalink]
Bunuel wrote:
A right cylindrical container with radius 2 meters and height 1 meter is filled to capacity with oil. How many empty right cylindrical cans, each with radius 1/2 meter and height 4 meters, can be filled to capacity with the oil in this container?


Volume of cylinder = π * r^2 * h

Volume 1 = π * 2^2 * 1 = 4π
Volume 2 = π * (1/2)^2 * 4 = π

Number of Cylinder = Volume 1 / Volume 2 = 4π / π = 4

Hence, C.
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Re: A right cylindrical container with radius 2 meters and height 1 meter [#permalink]
Bunuel wrote:
A right cylindrical container with radius 2 meters and height 1 meter is filled to capacity with oil. How many empty right cylindrical cans, each with radius 1/2 meter and height 4 meters, can be filled to capacity with the oil in this container?


(A) 1

(B) 2

(C) 4

(D) 8

(E) 16

Project PS Butler : Question #68


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Great question

So initial volume = pi r^2 h = 4 pi

Now this has to be filled in cylinders having volume as 1/4 * 4 * pi = pi

4 such cylinders can be filled

C
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Re: A right cylindrical container with radius 2 meters and height 1 meter [#permalink]
Bunuel wrote:
A right cylindrical container with radius 2 meters and height 1 meter is filled to capacity with oil. How many empty right cylindrical cans, each with radius 1/2 meter and height 4 meters, can be filled to capacity with the oil in this container?


(A) 1

(B) 2

(C) 4

(D) 8

(E) 16


Volume of the right cylindrical container is \(π*2^2*1 = 4π\)
Volume of empty right cylindrical cans is \(π*(\frac{1}{2})^2*4 = π\)

So, Total number of empty right cylindrical cans is \(\frac{4π}{π} = 4\), Answer must be (C)
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Re: A right cylindrical container with radius 2 meters and height 1 meter [#permalink]
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Re: A right cylindrical container with radius 2 meters and height 1 meter [#permalink]
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