anarchist112 wrote:

A's speed is 20/13 times that of B. If A and B run a race, what part of the length of the race should A give B as a head start, so that B beats A by 20% of the length of the race?

A. 44%

B. 48%

C. 52%

D. 42%

E. 46%

Another way to visualize this..

It is given to us that

\(\frac{A_{speed}}{B_{speed}} = \frac{20}{13}\)

let the race be of 20 units.

Now..when A completes 80% of the distance of the race..B will complete 80% of his distance according to the ratio..

\(0.8*13 = 10.4\)

But what we want..is that when A completes 80% of the race..B should complete the entire race..

So the head start will be

\(20 - 10.4 = 9.6 units\)

In terms of percentage of 20 units..it is

48%(B)

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