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# A saleswoman s monthly income has two components, a fixed

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GMAT Instructor
Joined: 04 Jul 2006
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A saleswoman s monthly income has two components, a fixed [#permalink]

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09 Jul 2006, 04:25
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A saleswomanâ€™s monthly income has two components, a fixed component of \$1000 per month, and a variable component, which is \$C for each set of encyclopaedias that she sells in that month over a sales target of n sets. How much did she earn in March?

(1) If she had sold three fewer sets, her March income would have been \$600 lower.
(2) If she had sold 8 sets of encyclopaedias, her income in March would have been over \$4000

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GMAT Instructor
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09 Jul 2006, 15:57
Any takers?

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Manager
Joined: 14 Mar 2006
Posts: 208

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Re: DS: Saleswoman [#permalink]

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09 Jul 2006, 17:06
kevincan wrote:
A saleswomanâ€™s monthly income has two components, a fixed component of \$1000 per month, and a variable component, which is \$C for each set of encyclopaedias that she sells in that month over a sales target of n sets. How much did she earn in March?

(1) If she had sold three fewer sets, her March income would have been \$600 lower.
(2) If she had sold 8 sets of encyclopaedias, her income in March would have been over \$4000

ummm, not sure but i'll take shot at it.
either E or C, i'll pick E.

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Manager
Joined: 26 Jun 2006
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09 Jul 2006, 18:03
I would have picked (E) too...

I know for sure I can eliminate (A), (B), and (D). Without comlpetely solving it, I am leaning toward (E)

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Senior Manager
Joined: 07 Jul 2005
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Location: Sunnyvale, CA
Re: DS: Saleswoman [#permalink]

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09 Jul 2006, 18:10
kevincan wrote:
A saleswomanâ€™s monthly income has two components, a fixed component of \$1000 per month, and a variable component, which is \$C for each set of encyclopaedias that she sells in that month over a sales target of n sets. How much did she earn in March?

(1) If she had sold three fewer sets, her March income would have been \$600 lower.
(2) If she had sold 8 sets of encyclopaedias, her income in March would have been over \$4000

(C)
I. implies, either C = 600, or 2C = 600, or 3C = 600
II. C(8-n) > 4000 --insufficient

Assuming, n to be a non-zero no. we get n = 1, C = 600, => sufficient

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VP
Joined: 02 Jun 2006
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09 Jul 2006, 19:53

Given Salary S = 1000 + C(n-t)

where t = target,
n = # of sets sold

S1: S' = S - 600

or 1000 + C(n-t) - 600 = 1000 + C(n-3-t)

Can compute C. Still don't know n, t

Not sufficient.

S2: If sold 8 sets, income over 4000
C(8-t) > 3000 Still don't know t or C. Not sufficient.

S1 & S2:

From S1 : can compute C
From S2 : Can compute t.

But we still don't know how many sets were *actually sold*. S2 just says "if 8 were sold"...
Insufficient.

Kudos [?]: 108 [0], given: 0

09 Jul 2006, 19:53
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# A saleswoman s monthly income has two components, a fixed

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