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Joined: 28 May 2005
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A school administrator will assign each student in a group [#permalink]
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07 Oct 2005, 14:46
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A school administrator will assign each student in a group of n students to one of m classrooms. If 3 < m < 13 < n, is it possible to assign each of the n students to one of the m classrooms so that each classroom has the same number of students assigned to it? (1) It is possible to assign each of 3n students to one of m classrooms so that each classroom has the same number of students assigned to it. (2) It is possible to assign each of 13n students to one of m classrooms so that each classroom has the same number of students assigned to it. OPEN DISCUSSION OF THIS QUESTION IS HERE: aschooladministratorwillassigneachstudentinagroup127509.html
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Director
Joined: 21 Aug 2005
Posts: 789

i think the answer is D
Question basically asks whether n/m is an integer.
from A, we can say 3(n/m) is an integer. So, n/m must be an integer.
This will fail if n=1 and m=3 and other lower numbers, but the range of values for n and m exclude this possibility.
Similarly with B.



Director
Joined: 21 Aug 2005
Posts: 789

I don't think it is D.
A) n=17 & m=7 > 3n/m is not an integer
B) n=15 & m=4 > 13n/m is not an integer
Both cases wont work
Is it E?
Last edited by gsr on 08 Oct 2005, 15:47, edited 3 times in total.



Intern
Joined: 14 Jun 2005
Posts: 37

I think ans should be B.
13n/m is an integer. And the question stem says 3<m<13<n
Suppose n = 14 [any no. greater than13] then for 13n/m to be an integer m has to be a factor of n. And so i think the statement alone is sufficient.
Lemme know if i am wrong.



SVP
Joined: 28 May 2005
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OA is A.
can anybody has any explnation.
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hey ya......



Director
Joined: 17 Oct 2005
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A school administrator will assign each student in a group of n students to one of m classrooms. If 3<m<13<n, is it possible to assign each of the n students to one of the m classrooms so that each classroom has the same number of students assigned to it?
1) it is possible to assign each of 3n students to one of m classrooms so that each classroom has the same number of students assigned to it
2) it is possible to assign each of 13n students to one of m classrooms so that each classroom has the same number of students assigned to it.



Director
Joined: 04 Jan 2006
Posts: 922

B?
If 13n is assigned to m classes... then the number n is surely divisible by m since m cannot be 13 or 1.. So we are sure that m can be divided into n..
Is that right?
OA?



Senior Manager
Joined: 05 Jan 2006
Posts: 381

I could not solve! but convinced with willget800 explaination!
btw where did you get this question!



VP
Joined: 21 Sep 2003
Posts: 1057
Location: USA

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willget800 wrote: B?
If 13n is assigned to m classes... then the number n is surely divisible by m since m cannot be 13 or 1.. So we are sure that m can be divided into n..
Is that right?
OA?
Good explanation.
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Senior Manager
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yeah! agree with willget800 , seems simple yet a good question!
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Director
Joined: 17 Oct 2005
Posts: 928

i am stuck here
using the same reasoning can't I be sufficent also?
3n/m , 3 is prime so n has to be divisible by m?



VP
Joined: 21 Sep 2003
Posts: 1057
Location: USA

joemama142000 wrote: i am stuck here
using the same reasoning can't I be sufficent also?
3n/m , 3 is prime so n has to be divisible by m?
For n = 14 and m = 6
3n/m is divisible but n/m is not!
For n=15, and m = 5 both 3n/m and n/m are divisible.
Hence 1 is INSUFF.
HTH
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"To dream anything that you want to dream, that is the beauty of the human mind. To do anything that you want to do, that is the strength of the human will. To trust yourself, to test your limits, that is the courage to succeed."
 Bernard Edmonds



Manager
Joined: 17 Jan 2006
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Another good DS [#permalink]
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02 May 2006, 03:00
A school administrator will assign each student in a group of n students to one of m classrooms. If 3 < m < 13 < n, is it possible to assign each of the n students to one of the m classrooms so that each classroom has the same number of students assigned to it?
(1) It is possible to assign each of 3n students to one of m classrooms so that eachclassroom has the same number of students assigned to it.
(2) It is possible to assign each of 13n students to one of m classrooms so that eachclassroom has the same number of students assigned to it.



Director
Joined: 13 Nov 2003
Posts: 789
Location: BULGARIA

Hallo,
Think that A is insufficient
From A) 3n=K*m now n15 then m can be 5 or 9 which makes A insuff
From B) 13n=K*m then m can not be a prime bigger than 13 , n=15 m can be 3 or 5, n=20 m can be 2,4,10
So think that B Is sufficient



Intern
Joined: 24 Apr 2006
Posts: 14

CAREFUL !
OA is not A but B !!!!
See http://www.gmatclub.com/phpbb/viewtopic ... inistrator for explanation !!!



Director
Joined: 06 May 2006
Posts: 791

#1. 3n/m is an integer.
Since m > 3, m could be a multiple of 3. However, n may or may not be a multiple of m.
e.g. n = 16, m = 12. or n = 15, m = 5
#2. 13n/m is an integer.
Since 13 > m, m cannot be a multiple of 13. Hence m has to be a factor of n. Sufficient.
B.
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Senior Manager
Joined: 07 Jul 2005
Posts: 404
Location: Sunnyvale, CA

Good question.
shd be (B)
exactly as paddyboy explained..



Intern
Joined: 27 Jun 2006
Posts: 1

Ive just decided to start studying for the gmat, so im a rookie here, but....
The question asks: is it possible to do so. and i think that (D) is correct b/c they both are sufficient to recognizing that it is possible.



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mthizzle wrote: Ive just decided to start studying for the gmat, so im a rookie here, but.... The question asks: is it possible to do so. and i think that (D) is correct b/c they both are sufficient to recognizing that it is possible.
This should be B.
In A if 3n = 42 and m = 6 then stem fails but if 3n = 48 and m = 4 then it works. So its INSUFF.
In B it works always.
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SAID BUSINESS SCHOOL, OXFORD  MBA CLASS OF 2008



SVP
Joined: 30 Mar 2006
Posts: 1728

B.
1) Say there are 14 students hence 42 students can be divided into m classrooms
M can be 6, 7 etc but with 6 classrooms, each classroom won't have equal number of students
2) Say there are 14 students hence 182 students can be divided into m class rooms
here we only get 7 classrooms....
Pick any other value for students and u will see you only get classrooms that are factors of students







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