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A school play requires 24 actors to be cast among boys, girls, and adu

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Re: A school play requires 24 actors to be cast among boys, girls, and adu [#permalink]

B on the contrary says that Adults / children = 1/3 -> or total we have 4 parts. minimum number of adults thus must be 6. if we have more or less adults, then the ratio is not good.
B is sufficient
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Re: A school play requires 24 actors to be cast among boys, girls, and adu [#permalink]
Bunuel wrote:
A school play requires 24 actors to be cast among boys, girls, and adults. If no actors may take two roles, how many adult actors are needed?

(1) The ratio of boys needed to girls is 2 to 1.
(2) The ratio of children needed to adults is 3 to 1.

We are given that a school play requires 24 actors to be cast among boys, girls, and adults, and we need to determine the number of adult actors needed.

Statement One Alone:

The ratio of boys needed to girls is 2 to 1.

Since statement one does not provide any information regarding the adults, statement one alone is not sufficient to answer the question.

Statement Two Alone:

The ratio of children needed to adults is 3 to 1.

Since the number of children is equal to the total number of boys and girls, we can create the following ratio:

Children : Adults = 3x : 1x

Since the total number of actors is 24, we can determine x with the following equation:

3x + 1x = 24

4x = 24

x = 6

Thus, the number of adults needed is 6. Statement two is sufficient.

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Re: A school play requires 24 actors to be cast among boys, girls, and adu [#permalink]