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# A school's annual budget for the purchase of student comp

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Manager
Status: And the Prep starts again...
Joined: 03 Aug 2010
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A school's annual budget for the purchase of student comp  [#permalink]

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01 Oct 2012, 09:51
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4
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Difficulty:

5% (low)

Question Stats:

86% (01:49) correct 14% (02:09) wrong based on 211 sessions

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A school’s annual budget for the purchase of student computers increased by 60% this year over last year. If the price of student computers increased by 20% this year, then the number of computers it can purchase this year is what percent greater than the number of computers it purchased last year?

A. 33.33%
B. 40%
C. 42%
D. 48%
E. 60%
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Joined: 02 Sep 2009
Posts: 64102
Re: A school's annual budget for the purchase of student comp  [#permalink]

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19 Jan 2014, 23:49
5
1
flower07 wrote:
Can somebody break this down for me? I am quite not getting it. Please?

A school’s annual budget for the purchase of student computers increased by 60% this year over last year. If the price of student computers increased by 20% this year, then the number of computers it can purchase this year is what percent greater than the number of computers it purchased last year?

A. 33.33%
B. 40%
C. 42%
D. 48%
E. 60%

Pick numbers.

Lats year: budget = \$100, price = \$1 --> the number of computers purchased = 100/1 = 100;

This year: budget = \$160, price = \$1.2 --> the number of computers purchased = 160/1.2 = ~133.33.

Increase in the number of computers purchased = 33.33%.

Hope it's clear.
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Re: A school's annual budget for the purchase of student comp  [#permalink]

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01 Oct 2012, 09:58
6
ENAFEX wrote:
A school's annual budget for the purchase of student computers increased by 60% this year over last year. if the price of student computers increased by 20% this year, then the number of computers it can purchase this year is what percent greater than the number of computers it purchased last year?

a. 33.33%
b. 40%
c. 42%
d. 48%
e. 60%

If last year, the budget was B and the price of one computer was P, then B/P was the number of purchased computers.
This year, 1.6B/(1.2P) = 4/3(B/P) = 1.33(B/P) computers can be purchased, which is 33.33% greater than the number of computers purchased last year.

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##### General Discussion
Intern
Joined: 20 Feb 2016
Posts: 4
Re: A school's annual budget for the purchase of student comp  [#permalink]

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31 Aug 2016, 04:55
1
Bunuel wrote:
flower07 wrote:
Can somebody break this down for me? I am quite not getting it. Please?

A school’s annual budget for the purchase of student computers increased by 60% this year over last year. If the price of student computers increased by 20% this year, then the number of computers it can purchase this year is what percent greater than the number of computers it purchased last year?

A. 33.33%
B. 40%
C. 42%
D. 48%
E. 60%

Pick numbers.

Lats year: budget = \$100, price = \$1 --> the number of computers purchased = 100/1 = 100;

This year: budget = \$160, price = \$1.2 --> the number of computers purchased = 160/1.2 = ~133.33.

Increase in the number of computers purchased = 33.33%.

Hope it's clear.

This truly is wonderfully explained.
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Joined: 28 Aug 2006
Posts: 236
Re: A school's annual budget for the purchase of student comp  [#permalink]

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02 Oct 2012, 03:33
ENAFEX wrote:
A school's annual budget for the purchase of student computers increased by 60% this year over last year. if the price of student computers increased by 20% this year, then the number of computers it can purchase this year is what percent greater than the number of computers it purchased last year?

a. 33.33%
b. 40%
c. 42%
d. 48%
e. 60%

Since the price is increased by 20%, for 120% of last year budget they get as many computers as they got last year, say n
For 160% they will get 160/120 = 4/3n
Hence 1/3n i.e. 33.33% more than last year
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Status: Aiming for 750+
Joined: 16 Oct 2013
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GMAT Date: 05-05-2014
Re: A school's annual budget for the purchase of student comp  [#permalink]

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19 Jan 2014, 23:38
Can somebody break this down for me? I am quite not getting it. Please?
Intern
Joined: 30 Jun 2019
Posts: 3
Re: A school's annual budget for the purchase of student comp  [#permalink]

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24 Nov 2019, 09:23
Last year Budget = \$100
01 Computer price = \$100
so number computer bought in last year = 01

This year Budget = \$160
01 Computer price = \$120

Number of computer can be bought in this year = Total Budget / Computer price = 160/ 120 = 1.33
% of number of computer is increased = (1.33 - 1)/ 100 = 33%
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GMAT 1: 600 Q46 V27
Re: A school's annual budget for the purchase of student comp  [#permalink]

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24 Nov 2019, 09:53
ENAFEX wrote:
A school’s annual budget for the purchase of student computers increased by 60% this year over last year. If the price of student computers increased by 20% this year, then the number of computers it can purchase this year is what percent greater than the number of computers it purchased last year?

A. 33.33%
B. 40%
C. 42%
D. 48%
E. 60%

Let's say your budget was 100 and computer was 100 too. So you could buy 1 computer.

Now you have 160 but the price is 120. So you can buy 1computer and 40/120 which is 33.33% more.

So technically you can buy 1.33 computers.
Option A.

Note: You can just ignore the fraction. You should realise for a higher appropriate value you will find an Integer value
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Re: A school's annual budget for the purchase of student comp   [#permalink] 24 Nov 2019, 09:53