A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7} : GMAT Problem Solving (PS)
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# A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7}

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Intern
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A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7} [#permalink]

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23 Jan 2011, 10:31
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Q) A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7} is defined with given numbers. Now one number is chosen randomly from each of the given set in such a way that the absolute difference between the two numbers is 2. What is the probability that one of the number chosen is 3?

(Sorry I don't have the answer choices for the question above.)
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Joined: 02 Sep 2009
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Kudos [?]: 96342 [2] , given: 10737

Re: A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7} [#permalink]

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23 Jan 2011, 10:48
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MichelleSavina wrote:
Q) A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7} is defined with given numbers. Now one number is chosen randomly from each of the given set in such a way that the absolute difference between the two numbers is 2. What is the probability that one of the number chosen is 3?

(Sorry I don't have the answer choices for the question above.)

Probability=# of favorable outcomes/total # of outcomes;

There are total of 8 (p,q) pairs possible so that the absolute difference between the two numbers to be 2: (1, 3), (2, 4), (3, 5), (3, 1), (4, 6), (4, 2), (5, 7), (5, 3) (first # is chosen from set P and second # is chosen from set Q). 4 pairs contain the number 3 in it, so P=4/8=1/2.
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Re: A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7} [#permalink]

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01 Nov 2015, 09:31
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Re: A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7} [#permalink]

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16 Nov 2016, 10:17
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7} [#permalink]

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11 Dec 2016, 20:03
Bunuel wrote:
MichelleSavina wrote:
Q) A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7} is defined with given numbers. Now one number is chosen randomly from each of the given set in such a way that the absolute difference between the two numbers is 2. What is the probability that one of the number chosen is 3?

(Sorry I don't have the answer choices for the question above.)

Probability=# of favorable outcomes/total # of outcomes;

There are total of 8 (p,q) pairs possible so that the absolute difference between the two numbers to be 2: (1, 3), (2, 4), (3, 5), (3, 1), (4, 6), (4, 2), (5, 7), (5, 3) (first # is chosen from set P and second # is chosen from set Q). 4 pairs contain the number 3 in it, so P=4/8=1/2.

Why not (7,5) (6,4) are taken in total
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Kudos [?]: 96342 [0], given: 10737

Re: A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7} [#permalink]

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12 Dec 2016, 00:10
himanshukamra2711 wrote:
Bunuel wrote:
MichelleSavina wrote:
Q) A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7} is defined with given numbers. Now one number is chosen randomly from each of the given set in such a way that the absolute difference between the two numbers is 2. What is the probability that one of the number chosen is 3?

(Sorry I don't have the answer choices for the question above.)

Probability=# of favorable outcomes/total # of outcomes;

There are total of 8 (p,q) pairs possible so that the absolute difference between the two numbers to be 2: (1, 3), (2, 4), (3, 5), (3, 1), (4, 6), (4, 2), (5, 7), (5, 3) (first # is chosen from set P and second # is chosen from set Q). 4 pairs contain the number 3 in it, so P=4/8=1/2.

Why not (7,5) (6,4) are taken in total

There is not 7 and there is no 6 in set P.
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Re: A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7}   [#permalink] 12 Dec 2016, 00:10
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