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A shipment of 250 smartphones contains 84 that are defecti

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Manager
Joined: 09 Feb 2013
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A shipment of 250 smartphones contains 84 that are defecti [#permalink]

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22 Mar 2013, 01:07
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A shipment of 250 smartphones contains 84 that are defective. If a customer buys two smartphones at random from the shipment, what is the approximate probability that both phones are defective?

A. 1/250
B. 1/84
C. 1/11
D. 1/9
E. 1/3
[Reveal] Spoiler: OA

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Director
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Joined: 05 Apr 2011
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Location: India
Concentration: Finance, Marketing
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Re: A shipment of 250 smartphones contains 84 that are defecti [#permalink]

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22 Mar 2013, 01:14
emmak wrote:
A shipment of 250 smartphones contains 84 that are defective. If a customer buys two smartphones at random from the shipment, what is the approximate probability that both phones are defective?
a)$$\frac{1}{250}$$
b)$$\frac{1}{84}$$
c)$$\frac{1}{11}$$
d)$$\frac{1}{9}$$
e)$$\frac{1}{3}$$

Probability of chosing one defective phone from a lot of 250 which ontains 84 defective phones is = (84/250)
Probability of chosing one defective phone from a lot of 249(we already picked one) which ontains 83(we already picked one) defective phones is = (83/249)

Combined probability of series of events = product of the probabilities = (84/250)*(83/249)

84/250 is close to (1/3) and (83/249)= (1/3)
so answer is (1/3)*(1/3) = (1/9)

Hope it helps!
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Re: A shipment of 250 smartphones contains 84 that are defecti [#permalink]

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08 Jul 2013, 14:43
Amm... this doesn't seem that difficult.

The only problem is quickly identifying that 84 is one third.

Chances of picking 1 defective phone = 84 / 250 = ~0.33 (25/8 is even faster)
Chances of picking 2 phones then = 0.33 x 0.33 = 1/3 x 1/3 = 1/9
If we need to go further = 1/3 x 1/3 x 1/3 = 1/27

Lotto goes on ))

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Re: A shipment of 250 smartphones contains 84 that are defecti [#permalink]

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08 Jul 2013, 15:48
same as what the other two said.

Probability that the first phone is defective is (84/250) ~ (80*3 = 240). Therefore the approximation is (1/3)
Assuming that the first is a favorable outcome, for the next phone there will only be (83/249). Again, the approximation is ~ (1/3)

Probability of both events happening = (1/3)*(1/3) = 1/9 = D

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Re: A shipment of 250 smartphones contains 84 that are defecti [#permalink]

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08 Jul 2013, 21:23
emmak wrote:
A shipment of 250 smartphones contains 84 that are defective. If a customer buys two smartphones at random from the shipment, what is the approximate probability that both phones are defective?

A. 1/250
B. 1/84
C. 1/11
D. 1/9
E. 1/3

$$84C2/250C2 = (84*83)/(250*249)= 14/125 = 1/9$$

Note: This is same as picking 2 red colored cards in random from a deck of 52 cards.....
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Re: A shipment of 250 smartphones contains 84 that are defecti [#permalink]

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28 Jul 2014, 22:21
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Re: A shipment of 250 smartphones contains 84 that are defecti [#permalink]

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26 May 2016, 02:46
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: A shipment of 250 smartphones contains 84 that are defecti [#permalink]

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26 May 2016, 09:06
emmak wrote:
A shipment of 250 smartphones contains 84 that are defective. If a customer buys two smartphones at random from the shipment, what is the approximate probability that both phones are defective?

A. 1/250
B. 1/84
C. 1/11
D. 1/9
E. 1/3

probability of selecting two defective phones= 84/250*83/249= 1/9

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Re: A shipment of 250 smartphones contains 84 that are defecti   [#permalink] 26 May 2016, 09:06
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