pushpitkc wrote:
A shipment of 500 bulbs contains 10% defective bulbs. If three bulbs are chosen
randomly, what is the probability that exactly 2 of them are defective?
A. \(\frac{1}{500}\)
B. \(\frac{3}{500}\)
C. \(\frac{3}{1000}\)
D. \(\frac{9}{1000}\)
E. \(\frac{27}{1000}\)
Source:
Experts Global Number of Defective Bulbs = 50
Number of Non-Defective Bulbs = 450
Ways of Selecting Exactly 2 Ddefective Bulbs & 1 non-Defective Bulb = \(50C2 * 450C1\)
Total Number of Ways = \(500C3.\)
Probability = \(50C2 * 450C1 / 500C3.\)
= 0.027
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