guygmat wrote:

A shop produces sarongs. The daily average production is given by 5n + 20, where n is the number of workers aside from the owner. In the first k days, 500 units are produced, and then 5 workers are added to the team. After another k days, the cumulative total is 1250. How many workers were part of the latter production run?

A)6

B)10

C)11

D)15

E)23.5

The daily average production is given by 5n + 20- given

In the first k days, 500 units are produced

= (5n+20)K =500

k = 500/5n+20...................................1

5 workers were added = 5(n+5)+20 = 5n +45

cumulative is 1250 .. thus for the current period = 1250 -500 = 750

(5n+45)K= 750

k = 750/5n+45........................................2

equate 1 and 2

500/5n+20 = 750 /5n+45

500(5n+45) = 750(5n+20)

2500n + 22500 = 3750n + 15000

-1250n = -7500

n = 6

thus n+5 = 11

hence C