adkikani wrote:

niks18 amanvermagmat Bunuelcouple of queries in solution by

shrive555**Quote:**

Small = 1/3

Big = 1/4

S = 5B

small = 1/3 =5B => 1/15

1/15 + 1/ 4 = 19/60 ..

Should it not be B = 5 * S

Also for solution provided by

Spidy001**Quote:**

fresh water in the large beaker = (5C)/4

Should it not be 5 * (C/3) * 1/4 ie 5C/12 ??

We are given that Another beaker

(ie bigger one), which has five times the capacity of the small beaker, is 1/4 filled with fresh water.

Hi

adkikani,

Just a small suggestion, for these kind of fraction related questions it's Easiest to solve through SMART NUMBERS rather than algebra.

so here we have fractions \(\frac{1}{3}\) & \(\frac{1}{4}\), so let's assume capacity of small beaker be \(12\) (LCM of 3 & 4)

So capacity of Large beaker \(= 12*5=60\)

Small is filled till \(12*\frac{1}{3}=4\) units and large is filled till \(60*\frac{1}{4}=15\) units.

So when contents of small beaker is poured in large beaker, it's total content will be \(= 4+15=19\) units.

Hence fraction filled \(= \frac{19}{60}\)

Now coming to your question - I do not see any problem with Spidy001's solution. Can you explain why you think it should be C/3 and not C?

with shrive555's solution, I think the notation is wrong but somehow he/she has got the right answer