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Answer is A just took a paper base gmat test. Had to guess on this one since I was running out of time. Look simple in the beginning until you needed to factor. Turned out to be a trap.

L+w=280 l=280-w
l^2+w^2=200^2
w^2-280w+19200=)
w(w-280)=-19200
take out the negative num
-w(280-w)=-19200 --> w(280-w)=19200
Area = w(280-w) answer 19200

Answer is A just took a paper base gmat test. Had to guess on this one since I was running out of time. Look simple in the beginning until you needed to factor. Turned out to be a trap.

L+w=280 l=280-w l^2+w^2=200^2 w^2-280w+19200=) w(w-280)=-19200 take out the negative num -w(280-w)=-19200 --> w(280-w)=19200 Area = w(280-w) answer 19200

Yeah, I substituted the first equation into the second and got: w^2-280w+19200=0

Then I broke down 19200 to get the factors (w-160)(w-120)=0

Either way, the area comes to 19,200

What's the shortcut here??

Last edited by GMATT73 on 22 Aug 2006, 08:28, edited 1 time in total.

hmm. interesting. I ddi the calc in my head but now I will look at it again.

BTW - Can you answer this one?

Data Sufficiency - Section 6 -#20
The symbol @ represents one of the following operations: addition, subtraction, multiplication, or division. What is the value of 3@2?

hmm. interesting. I ddi the calc in my head but now I will look at it again.

BTW - Can you answer this one?

Data Sufficiency - Section 6 -#20 The symbol @ represents one of the following operations: addition, subtraction, multiplication, or division. What is the value of 3@2?

1) 0@1=1 2) 1@0=1

Answer should be A

From Statement 1 - @ can only be '+' only hence 3@2 = 3+2 = 5

From Statement 2 - 1@0=1 implies @ could be '+' or '-' which would give you 2 different answers for 3@2 (NOT SUFF)

The text book answer is A, But I'm confused because technically you could switch the numbers - meaning in data point 1) could be 0+1=1 OR it could be 1-0=1, in the latter, this would translate to 2-3=-1, while the former would translate to 3+2=5 and thus A alone is insufficient.

Does anyone have a solution to this?

Now this one. This one is giving me a lot of trouble as well.

21. Are the numbers K/4, Z/3, R/2 in increasing order?

The text book answer is A, But I'm confused because technically you could switch the numbers - meaning in data point 1) could be 0+1=1 OR it could be 1-0=1, in the latter, this would translate to 2-3=-1, while the former would translate to 3+2=5 and thus A alone is insufficient.

Does anyone have a solution to this?

Now this one. This one is giving me a lot of trouble as well.

21. Are the numbers K/4, Z/3, R/2 in increasing order?

1)3<Z<4 2)R<Z<K

Unless the stem specifies that you can switch the numbers, we have to do the calculations in the order given. Somebody here once said it right: Assume nothing. Only (A) stands.

Well thank you very much for clarifying that for me. I would have made teh assumption that the "@" function could be interpreted in any way possible. Its still baffling to me that you have to take the numbers in the order given but I guess for now its one of those things I will have to accept.

by the way, i think answer to the R,Z,K question posted by sandi is E

stem 1 => z is a positive number between 3 and 4

stem 2 => R is less than Z and K is greater than Z. So K is a positive number, whereas R can be a positive or negative number of any magnitude. So, you can't tell for sure what relationship K/4, Z/3 and R/2 have.
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What I did was to recognize that 200:280=5:7=5: (3+4) since 3,4,5 is a typical triangle. So I know that the two sides are 3*40 and 4*40 and the area is 12*1600=19200. Just to give an alternative approach.
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Last edited by HongHu on 24 Aug 2006, 08:25, edited 1 time in total.

What I did was to recognize that 200:280=5:7=5:(3+4) since 3,4,5 is a typical triangle. So I know that the two sides are 3*40 and 4*40 and the area is 12*1600=19200. Just to give an alternative approach.

HongHu is awesome as usual
Gr8 approach
_________________

What I did was to recognize that 200:280=5:7=5:(3+4) since 3,4,5 is a typical triangle. So I know that the two sides are 3*40 and 4*40 and the area is 12*1600=19200. Just to give an alternative approach.