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Re: A solid metal cylinder with radius 6 and height 3 is melted down, and [#permalink]
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A solid metal cylinder with radius 6 and height 3 is melted down, and all of the metal is used to recast a new solid cylinder with radius 3. What is the height of the new cylinder?

Volume of cylinder = \(\pi r^2 h\)

Volume of initial cylinder = \(\pi6^2\) 3 = 108\(\pi\)

Volume of new cylinder = \(\pi 3^2 h \) = 9h\(\pi\)

108\(\pi\) = 9h\(\pi\)

Solving for h, we get H= 12

Ans D
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Re: A solid metal cylinder with radius 6 and height 3 is melted down, and [#permalink]
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CONCEPT: Volume of 3D figures.
-Volume of a cylinder= ∏r^2h (r=radius of base; h=height of cylinder)

SOLUTION:
Volume of the old cylinder(V1)= ∏*(6)^2*3=∏*36*3
Volume of the new cylinder(V2) = ∏*(3)^2*h =∏*9*h ;(h=height of the new cylinder)
Volume of the metal remaining unchanged, we have V1=V2
Thus, ∏*36*3 = ∏*9*h
=>h=12 units.(D)

Hope this helps. :)
Keep studying :thumbsup:
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Re: A solid metal cylinder with radius 6 and height 3 is melted down, and [#permalink]
IMO ANS D
(pie) X (6X6) = (pie) X (3x3) X H
=> H = 12


Bunuel wrote:
A solid metal cylinder with radius 6 and height 3 is melted down, and all of the metal is used to recast a new solid cylinder with radius 3. What is the height of the new cylinder?

A. 6
B. 8
C. 10
D. 12
E. 15


Project PS Butler


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Re: A solid metal cylinder with radius 6 and height 3 is melted down, and [#permalink]
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