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Straight E. Alligative method (as neatly performed in gmat1220's post above) precipitates (forgive the pun) the solution (another pun) to the question faster.

Quick arithmetic works too, but the important advice is to decide quickly and firmly what method you want to use. And stick with it.

Concentration: General Management, Social Entrepreneurship

GMAT 1: 630 Q45 V33

GMAT 2: 700 Q47 V40

GPA: 3.78

Re: A solution of 60 ounces of sugar and water is 20% sugar. How [#permalink]

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09 Oct 2012, 13:16

mbaiseasy wrote:

Fast Technique. Thanks to GMATClub!

I've done mixtures questions before, and maybe this is just me not getting it because my brain is all curdled up right now, so forgive me for my ignorance.

Shouldn't x = 48 oz (which is the amount of water in it)?

And therefore, 3x = 144 oz?

I too get the 1:3 ratio. But maybe I'm missing something here.

Re: A solution of 60 ounces of sugar and water is 20% sugar. How [#permalink]

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09 Oct 2012, 15:09

1

This post received KUDOS

No sir. Everything in the above diagram is set up in terms of Total weights of solutions (water + sugar) and not the weight of water alone. The individual weights of sugar or sugar are implied in the percentage concentrations (5%, 0%, and 20%). Therefore x= Total weight of 20% solution = 60 oz. Not 48 oz., which represents the weight of water alone in the 20% solution

dpvtank wrote:

mbaiseasy wrote:

Fast Technique. Thanks to GMATClub!

I've done mixtures questions before, and maybe this is just me not getting it because my brain is all curdled up right now, so forgive me for my ignorance.

Shouldn't x = 48 oz (which is the amount of water in it)?

And therefore, 3x = 144 oz?

I too get the 1:3 ratio. But maybe I'm missing something here.

Concentration: General Management, Social Entrepreneurship

GMAT 1: 630 Q45 V33

GMAT 2: 700 Q47 V40

GPA: 3.78

Re: A solution of 60 ounces of sugar and water is 20% sugar. How [#permalink]

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09 Oct 2012, 15:41

OldFritz wrote:

No sir. Everything in the above diagram is set up in terms of Total weights of solutions (water + sugar) and not the weight of water alone. The individual weights of sugar or sugar are implied in the percentage concentrations (5%, 0%, and 20%). Therefore x= Total weight of 20% solution = 60 oz. Not 48 oz., which represents the weight of water alone in the 20% solution

Re: A solution of 60 ounces of sugar and water is 20% sugar. How [#permalink]

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09 Oct 2014, 17:12

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