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# A store currently charges the same price per pound of salad. If the cu

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Math Revolution GMAT Instructor
Joined: 16 Aug 2015
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A store currently charges the same price per pound of salad. If the cu  [#permalink]

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09 May 2017, 00:33
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Difficulty:

65% (hard)

Question Stats:

54% (02:16) correct 46% (02:34) wrong based on 103 sessions

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A store currently charges the same price per pound of salad. If the current price per pound were to be increased by \$0.2, 0.5 pound smaller salad could be bought for \$9. What is the current price of salad per pound?

A. \$1.6
B. \$1.7
C. \$1.72
D. \$1.8
E. \$1.84

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Re: A store currently charges the same price per pound of salad. If the cu  [#permalink]

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09 May 2017, 01:30
Is there a more efficient way to solve it than value substitution? If yes, could you please explain the same?
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Re: A store currently charges the same price per pound of salad. If the cu  [#permalink]

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09 May 2017, 11:35
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Re: A store currently charges the same price per pound of salad. If the cu  [#permalink]

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09 May 2017, 22:13
2
IMO, the best option is go from answer choices.
Let the price per pound of salad be x, size per salad be y
(x+0.2)(y-0.5) = 9 = xy
Since we have the price per pound, substitute the answer choices and see which of them makes sense.

In considering choice A, x=1.6
1.8(y-0.5) = 9
1.8y = 9.9
y = 5.5 Here, the value of xy is not 9 (1.6*5)

Consider choice B, x=1.7
1.9(y-0.5) = 9
1.9y = 9.95
y = 5.24
Here, the value of xy is not 9 (1.7*5.24)

Consider choice D, x=1.8
2(y-0.5) = 9
2y = 10
y = 5
Here, the value of xy is 9 (1.8*5)

(Option D)
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Re: A store currently charges the same price per pound of salad. If the cu  [#permalink]

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11 May 2017, 00:25
==> If you set the price of the salad per pound as \$p, for n pounds, you get np=(n-0.5)(p+0.2)=9. From np=np+0.2n-0.5p-0.1, if you substitute 0.2n=0.5p+0.1, and n=2.5p+0.5, you get p=1.8.

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Re: A store currently charges the same price per pound of salad. If the cu  [#permalink]

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04 Jun 2018, 02:20
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Re: A store currently charges the same price per pound of salad. If the cu   [#permalink] 04 Jun 2018, 02:20
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