Harshgmat wrote:

A store had a total of a pens which it sold. The store first sold b of these pens for c dollars each and it sold the remaining pens for 2c/3 dollars each. Which of the following is equal to the total amount of money the store received for the a pens, in dollars?

A) (2a + b)c/3

B) (a + 2b)c/3

C) (2a + 3b)c/3

D) (2a + c)b/3

E) (3a + 2b)c/3

The total pens the store had was

a pens. It sold the first b pens for c dollars.

Now, the remaining a - b pens that were left were sold for \(\frac{2c}{3}\) dollars each.

The total money recovered from the sale of pens is calculated as follows:

\(bc + (a-b)\frac{2c}{3} = \frac{3bc + 2ac - 2bc}{3} = \frac{bc + 2ac}{3} = \frac{c}{3}(2a + 3b)\)( after taking out \(\frac{c}{3}\) as common)

Therefore, the total amount of money the store received for the pens, in dollars is \((2a + 3b)\frac{c}{3}\)

(Option C)
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