Bunuel wrote:

A team of workers including Tom and Dick work in the same office according to a schedule that ensures that exactly two team members will be present at a given time, and that in the course of the week all the team members work an equal number of hours. What is the probability that a visitor to the office who doesn’t know the schedule arrives to find both Tom and Dick in the office?

(1) The team has three members.

(2) Tom and Dick worked together for the whole of the previous day.

(1) The team has three members.

So based on the stimulus there has to be two members present in the office

Possiblities are :-{Tom & Dick} {Tom & Unnamed Member} {Dick & Unnamed member} ; Total 3 possibilities ; Favorable = 1 {Tom & Dick }; Probablity = 1/3

(2) Tom and Dick worked together for the whole of the previous day.

First we do not know how many work days are in the thier companies week. Is it monday to saturday or Monday to Friday

We do not what time table the company follows.

MONDAY= TOM AND DICK----->THIRD ONE ON HOLIDAY

TUESDAY=TOM AND DICK ----------> THIRD ONE ON HOLIDAYWEDNESDAY=TOM AND THIRD ----> DICK ON HOLIDAY

THURSDAY=DICK AND THIRD-----> TOM ON HOLIDAY

FRIDAY= DICK AND THIRD -----> TOM ON HOLIDAY

SATURDAY =TOM AND THIRD ---> DICK ON HOLIDAY

SUNDAY= ALL THREE WORK

ALL WORK 5 DAYS AND ALL TAKE 2 DAYS LEAVE

Now we dont know when the stranger will come to visit.

If he comes on Tuesday, he has 100% probability of finding both tom and dick

If he comes on Wednesday, he has 0% probablity of finding both tom and dick

INSUFFICIENT

ANSWER IS A
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