It is currently 25 Sep 2017, 21:02

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

### Show Tags

05 Aug 2006, 08:09
3
This post was
BOOKMARKED
00:00

Difficulty:

65% (hard)

Question Stats:

60% (01:37) correct 40% (01:38) wrong based on 172 sessions

A total of $60,000 was invested for one year. Part of this amount earned simple annual interest at the rate of x percent per year, and the rest earned simple annual interest at the rate of y percent per year. If the total interest earned by the$60,000 for that year was $4,080, what is the value of x ? (1) $$x = \frac{3y}{4}$$ (2) The ratio of the amount that earned interest at the rate of x percent per year to the amount that earned interest at the rate of y percent per year was 3 to 2. [Reveal] Spoiler: OA Kudos [?]: 16 [0], given: 0 Senior Manager Joined: 14 Jul 2005 Posts: 402 Kudos [?]: 31 [0], given: 0 ### Show Tags 05 Aug 2006, 10:28 D From 1 => x/100 * 60,000 + 4x/3 * 100 * 60,000 = 4080 From 2 => 3a + 2a = 4080 => a = 816 Hence x/100 * 60,000 = 3 * 816 Hence you can solve for x using either equation Kudos [?]: 31 [0], given: 0 Manager Joined: 20 Mar 2006 Posts: 200 Kudos [?]: 4 [0], given: 0 Re: investment [#permalink] ### Show Tags 05 Aug 2006, 11:31 ong wrote: A total of$60,000 was invested for one year. Part of this amount earned simple annual interest at the rate of x percent per year, and the rest earned simple annual interest at the rate of y percent per year. If the total interest earned by the $60,000 for that year was$4,080, what is the value of x?
(1)x = 3y/4
(2)The ratio of the amount that earned interest at the rate of x percent per year to the amount that earned interest at the rate of y percent per year was 3 to 2.

(1) gives relationship between x and y. we still dont know the number of months to get a numerical value for x
Insuff BCE
(2) gives the ratio of Interest from x/Interest from y. Cannot determine x from this. CE
(1) & (2) No new information about the number of months

E

Heman

Kudos [?]: 4 [0], given: 0

Manager
Joined: 20 Mar 2006
Posts: 200

Kudos [?]: 4 [0], given: 0

### Show Tags

05 Aug 2006, 11:35
[quote="gmatornot"]D

From 1 => x/100 * 60,000 + 4x/3 * 100 * 60,000 = 4080
(1) I thought SI formula was prinicpal * rate * number of months/100. How are you getting x/100 * 60000.
(2) From the question stem i understand that part of the 60000 was invested @ x% and the rest @ y% ?

Kudos [?]: 4 [0], given: 0

Senior Manager
Joined: 14 Jul 2005
Posts: 402

Kudos [?]: 31 [0], given: 0

### Show Tags

05 Aug 2006, 15:40
heman wrote:
gmatornot wrote:
D

From 1 => x/100 * 60,000 + 4x/3 * 100 * 60,000 = 4080
(1) I thought SI formula was prinicpal * rate * number of months/100. How are you getting x/100 * 60000.
(2) From the question stem i understand that part of the 60000 was invested @ x% and the rest @ y% ?

You are RIGHT. I completely misread the question. I believe the answer is E as you have identified...

Kudos [?]: 31 [0], given: 0

Senior Manager
Joined: 22 May 2006
Posts: 367

Kudos [?]: 143 [0], given: 0

Location: Rancho Palos Verdes

### Show Tags

05 Aug 2006, 16:30
ong wrote:
A total of $60,000 was invested for one year. Part of this amount earned simple annual interest at the rate of x percent per year, and the rest earned simple annual interest at the rate of y percent per year. If the total interest earned by the$60,000 for that year was $4,080, what is the value of x? (1)x = 3y/4 (2)The ratio of the amount that earned interest at the rate of x percent per year to the amount that earned interest at the rate of y percent per year was 3 to 2. Let part of amount = A, then the other part = 60000-A A*(x/100) + (60000-A)*(y/100) = 4080 S1. x=3y/4 A*(3y/400) + (60000-A)*(y/100) = 4080 We need value A to solve this. => insufficient. S2. A*(x/100) = (3/5)*4080 = 2448 (60000-A)*(y/100) = (2/5)*4080= 1632 We need value A to solve this. => insufficient. Combine S1 and S2. A*(3y/400) = 2448 => A=2448*400/3y=326400/y (60000-A)*(y/100) = 1632 We have two variables with two eq. thus sufficient. Hence, C.. (600-3264/y)*(y) = 1632 600y - 3264 = 1632 600y = 1632+3264 600y = 4896 y = 8.16 % x=3y/4 = 8.16*3/4 = 6.12% _________________ The only thing that matters is what you believe. Kudos [?]: 143 [0], given: 0 Senior Manager Joined: 22 May 2006 Posts: 367 Kudos [?]: 143 [0], given: 0 Location: Rancho Palos Verdes Re: investment [#permalink] ### Show Tags 05 Aug 2006, 16:33 heman wrote: (1) & (2) No new information about the number of months E Heman If the total interest earned by the$60,000 for that year was $4,080, what is the value of x _________________ The only thing that matters is what you believe. Kudos [?]: 143 [0], given: 0 Manager Joined: 20 Mar 2006 Posts: 200 Kudos [?]: 4 [0], given: 0 Re: investment [#permalink] ### Show Tags 05 Aug 2006, 16:48 freetheking wrote: heman wrote: (1) & (2) No new information about the number of months E Heman If the total interest earned by the$60,000 for that year was $4,080, what is the value of x I still dont get it. Wouldnt it be possible for amount A @ x% for n months + amount (60000 - A) @ y % for (12-n) months = 4080. Then won't we have different value for x and y depending on the time period of investment within a year? Or does the ? mean that each part invested @ x% and y% was for a year? I had a similar solution to you except I had a variable for time period and so 2 eqns and 3 variables. Heman Kudos [?]: 4 [0], given: 0 Senior Manager Joined: 22 May 2006 Posts: 367 Kudos [?]: 143 [0], given: 0 Location: Rancho Palos Verdes Re: investment [#permalink] ### Show Tags 05 Aug 2006, 16:52 ong wrote: A total of$60,000 was invested for one year. Part of this amount earned simple annual interest at the rate of x percent per year, and the rest earned simple annual interest at the rate of y percent per year. If the total interest earned by the $60,000 for that year was$4,080, what is the value of x?

x and y are simple annual interest..
dealing with one year investment.. not monthly..
heman wrote:
Or does the ? mean that each part invested @ x% and y% was for a year?
Yes!
Heman

_________________

The only thing that matters is what you believe.

Kudos [?]: 143 [0], given: 0

Manager
Joined: 01 Jan 2008
Posts: 222

Kudos [?]: 61 [0], given: 2

Schools: Booth, Stern, Haas

### Show Tags

19 Jan 2008, 10:01
marcodonzelli wrote:
A total of $60,000 was invested for one year. Part of this amount earned simple annual interest at the rate of x percent per year, and the rest earned simple annual interest at the rate of y percent per year. If the total interest earned by the$60,000 for that year was $4,080, what is the value of x? (1) x = 3/4 y (2) The ratio of the amount that earned interest at the rate of x percent per year to the amount that earned interest at the rate of y percent per year was 3 to 2. I think it is C First statement is not suff because we don't know which amount was exactly invested, second is not suff since we don't know the rates but combined we can solve it II. 3/5*60000=36000 I. 36000*3/4y+24000*y=4,080 17/4y=4080/12000 => y=8% => x=8*3/4 =6% Kudos [?]: 61 [0], given: 2 Manager Joined: 10 Aug 2009 Posts: 129 Kudos [?]: 74 [0], given: 10 Re: DS: Interests ratios [#permalink] ### Show Tags 23 Aug 2009, 20:54 1)n1+ n2 = 60000 n1- amount invested at x%, n2 - amount invested at y%. 2) n1*x%+n2*y% = 4080 To solve this for x, we need two things: 1) the ratio of n1 to n2 (given in the second statement) 2) the ration of x to y (given in the first statement) So, both statements together are sufficient. Kudos [?]: 74 [0], given: 10 Senior Manager Joined: 30 Aug 2009 Posts: 285 Kudos [?]: 186 [0], given: 5 Location: India Concentration: General Management Re: annual interest [#permalink] ### Show Tags 29 Dec 2009, 08:31 kirankp wrote: A total of$60,000 was invested for one year. Part of this amount earned simple annual interest at the rate of x percent per year, and the rest earned simple annual interest at the rate of y percent per year. If the total interest earned by the $60,000 for that year was$4,080, what is the value of x?

(1) x = 3y/4

(2) The ratio of the amount that earned interest at the rate of x percent per year to the amount that earned interest at the rate of y percent per year was 3 to 2.

will go with C

let "a" be the amount which gets Simple interest at rate of x%/yr. Then SI = ax/100
then "60000 -a " is the amount which gets Simple interest at rate of y%/yr. Then SI = (60000-a)y/100

so we have (ax)/100 + (60000-a)y/100 = 4080

from stmnt 1- we have x = 3y/4 . even after substituting value of x in above equation we will not be able to get the value of x. Insuff

from stmnt 2 - we have (ax/100)/ (60000-a)y/100 =3/2. Again not suff

taking together x = 3y/4 and (ax/100)/ (60000-a)y/100 =3/2 we will get the value of x. hence suff

Kudos [?]: 186 [0], given: 5

Math Expert
Joined: 02 Sep 2009
Posts: 41718

Kudos [?]: 124994 [1], given: 12079

### Show Tags

26 Aug 2010, 11:26
1
KUDOS
Expert's post
udaymathapati wrote:
A total of $60,000 was invested for one year. But of this amount earned simple annual interest at the rate of x percent per year, and the rest earned simple annual interest at the rate of y percent per year. If the total interest earned by the$60,000 for that year was

### Show Tags

24 Jul 2014, 16:59
Let A be the part that gets interest at the rate of x% B = 60000 -A that gets interest at y%. There are two unknowns in question stem - the relation between A and B and the relation between x and y
Statement 1 : gives relation between x and y, but we do not know relation between A and B --> insufficient
Statement 2 gives A:B = 3:2, --> A = 36000 and B = 24000 but nothing about x:y, --> Insufficient

Combining 1 and 2 --> Can be solved as equation can be reduced to one variable , hence sufficient

Kudos [?]: 23 [0], given: 82