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# A Town T has 20,000 residents, 60 percent of whom are female. What per

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A Town T has 20,000 residents, 60 percent of whom are female. What per [#permalink]

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21 Feb 2011, 07:06
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A Town T has 20,000 residents, 60 percent of whom are female. What percent of the residents were born in Town T?

(1) The number of female residents who were born in Town T is twice the number of male residents who were not born in Town T.
(2) The number of female residents who were not born in Town T is twice the number of female residents who were born in Town T.

OPEN DISCUSSION OF THIS QUESTION IS HERE: a-town-t-has-20-000-residents-60-percent-of-whom-are-fem-al-166785.html
[Reveal] Spoiler: OA

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Last edited by Bunuel on 07 Jun 2015, 04:45, edited 1 time in total.
Renamed the topic and edited the question.
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Re: A Town T has 20,000 residents, 60 percent of whom are female. What per [#permalink]

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21 Feb 2011, 07:20
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A Town T has 20,000 residents, 60 percent of whom are female. What percent of the residents were born in Town T?

This question can be best described using a table. I don't know how would I draw that. Someone please suggest.

Female=12000
Male=8000

Female born in T=x
Female not born in T=12000-x

Male born in T=y
Male not born in T= 8000-y

(1) The number of female residents who were born in Town T is twice the number of male residents who were not born in Town T.
x=2*y
Not sufficient.

(2) The number of female residents who were not born n Town T is twice the number of female residents who were born in Town T.
12000-x=2x
3x = 12000
x=4000
We know the number of female born in T; 4000; Number of females not born; 8000
Know nothing about the male born in T i.e. y.

Combining both;
x=2y
4000 = 2y
y=2000

Total people born in T=2000+4000=6000 or (6/20)*100=30%
Sufficient.

Ans: "C"
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Re: A Town T has 20,000 residents, 60 percent of whom are female. What per [#permalink]

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21 Feb 2011, 08:10
it will be x = 2*(8000-y) but that doesn't change the answer.
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Re: A Town T has 20,000 residents, 60 percent of whom are female. What per [#permalink]

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14 Aug 2011, 06:01
A Town T has 20,000 residents, 60 percent of whom are female. What percent of the residents were born in Town T?

(1) The number of female residents who were born in Town T is twice the number of male residents who were not born in Town T.

(2) The number of female residents who were not born n Town T is twice the number of female residents who were born in Town T.
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Re: A Town T has 20,000 residents, 60 percent of whom are female. What per [#permalink]

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14 Aug 2011, 09:50
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It should be 3 equations to 3 unknowns, C sufficient.

For some reason I can't seem to find the answers though, maybe some number is wrong?

EDIT: couldn't get it right, got frustrated, searched the net. The original version of the problem seems to be:

(1) The number of female residents who were born in Town T is twice the number of male residents who were not born in Town T.

(2) The number of female residents who were not born in Town T is twice the number of female residents who were born in Town T.

Also: qr-ds-109774.html
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Re: A Town T has 20,000 residents, 60 percent of whom are female. What per [#permalink]

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16 Aug 2011, 08:00
the question seems to be incorrect..
in the final equation, i get total male as 6000 whereas the question gives 8000..
experts, any comments??
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Re: A Town T has 20,000 residents, 60 percent of whom are female. What per [#permalink]

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16 Aug 2011, 14:04
I guess some issue in the question. C should be the answer, but not able to solve the equations.
Then E is the answer as we are not able to solve.
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Re: A Town T has 20,000 residents, 60 percent of whom are female. What per [#permalink]

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17 Aug 2011, 11:30
jansam123 wrote:
I guess some issue in the question. C should be the answer, but not able to solve the equations.
Then E is the answer as we are not able to solve.

Born = B
Not Born = N
Female = F
Male = M
Total = T

After Statement -1

F M T
B 2x - -
N - x ?
T 12 8 20

Can't calculate NT, NOT Sufficient

After Statement -2

F M T
B 2x - -
N 4x - ?
T 12 8 20

Can't calculate NT, NOT Sufficient

Combining both, can calculate for x = 5

F M T
B 2x - -
N 4x x ?
T 12 8 20

=>

F M T
B 4 - -
N 8 2 10
T 12 8 20

So both together are Sufficient
Answer C
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Re: A Town T has 20,000 residents, 60 percent of whom are female. What per [#permalink]

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17 Aug 2011, 11:31
Sorry, I tried to make it more understandable but it seems formatting doesn't work
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Re: A Town T has 20,000 residents, 60 percent of whom are female. What per [#permalink]

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18 Aug 2011, 11:29
let's make a table and write all values from stem, statement 1 & 2

From Stem, total females = 60% of 20,000 = 12,000
From statement 1, if male(M) not born (NB) in town T are x, then female(F) born(B) in town = 2x
From statement 2, F(NB) = 2 F(B)
Combining both the statements, we have following table

| M | F |
-------|-------|------- |---------
B | | 2x |
-------|-------|------- |--------
NB | x | 2(2x) |
-------|-------|--------|------------
| | 12000 |

So, 2x + 2(2x) = 12,000.

Rest is all arithmetic, we can calculate each cell, hence final answer. Remember no need to go fro exact answer. We now know, both statements are sufficient. Answer is C.
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Re: A Town T has 20,000 residents, 60 percent of whom are female. What per [#permalink]

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Re: A Town T has 20,000 residents, 60 percent of whom are female. What per [#permalink]

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07 Jun 2015, 04:47
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A Town T has 20,000 residents, 60 percent of whom are female. What percent of the residents were born in Town T?

(1) The number of female residents who were born in Town T is twice the number of male residents who were not born in Town T.

Not sufficient.

(2) The number of female residents who were not born in Town T is twice the number of female residents who were born in Town T.

Not sufficient.

(1)+(2)

Sufficient.

Answer: C.

OPEN DISCUSSION OF THIS QUESTION IS HERE: a-town-t-has-20-000-residents-60-percent-of-whom-are-fem-al-166785.html
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Re: A Town T has 20,000 residents, 60 percent of whom are female. What per   [#permalink] 07 Jun 2015, 04:47
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