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A train of length L is traveling at a constant velocity and passes a [#permalink]

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02 Jul 2010, 23:35

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A train of length L is traveling at a constant velocity and passes a pole in t seconds. If the same train travelling at the same velocity passes a platform in 3t seconds then what is the length of the platform:

Concentration: International Business, Entrepreneurship

GMAT Date: 01-30-2012

GPA: 3

WE: Consulting (Computer Software)

Re: A train of length L is traveling at a constant velocity and passes a [#permalink]

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03 Jul 2010, 01:33

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A train of length L is traveling at a constant velocity and passes a pole in t seconds. If the same train travelling at the same velocity passes a platform in 3t seconds then what is the length of the platform: A) 0.5 L B) L C) 1.5 L D) 2 L E) 3 L

Sol: Length of train=Distance=L time to cross the pole=time=t so speed=L/t

new time=3t. so distance travelled= 3t*L/t = 3L

the distance is equal to train length L+platform length = 3L so platform is 2L. ans is D.
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Re: A train of length L is traveling at a constant velocity and passes a [#permalink]

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03 Jul 2010, 12:08

appy001 wrote:

A train of length L is traveling at a constant velocity and passes a pole in t seconds. If the same train travelling at the same velocity passes a platform in 3t seconds then what is the length of the platform: A) 0.5 L B) L C) 1.5 L D) 2 L E) 3 L

Sol: Length of train=Distance=L time to cross the pole=time=t so speed=L/t

new time=3t. so distance travelled= 3t*L/t = 3L

the distance is equal to train length L+platform length = 3L so platform is 2L. ans is D.

Ahh - very sneaky question! It's easy to forget that the entire train has to pass by the platform, so it travels the extra L distance.

Re: A train of length L is traveling at a constant velocity and passes a [#permalink]

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31 Oct 2014, 23:47

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Re: A train of length L is traveling at a constant velocity and passes a [#permalink]

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01 Nov 2014, 05:40

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shamikba wrote:

A train of length L is traveling at a constant velocity and passes a pole in t seconds. If the same train travelling at the same velocity passes a platform in 3t seconds then what is the length of the platform: A) 0.5 L B) L C) 1.5 L D) 2 L E) 3 L

Re: A train of length L is traveling at a constant velocity and passes a [#permalink]

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20 Dec 2014, 21:38

Length of pole is assumed 0. From case 1 we get the speed of the train =L/t In case 2 we need distance =speed x time =L/t x 3t=3L, but this 3L is the total distance inclusive of the length of the train which is L. so length of the platform =3L-L=2L. Hope this explanation helps.

Re: A train of length L is traveling at a constant velocity and passes a [#permalink]

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24 Jan 2016, 09:01

Hello from the GMAT Club BumpBot!

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A train of length L is traveling at a constant velocity and passes a pole in t seconds. If the same train travelling at the same velocity passes a platform in 3t seconds then what is the length of the platform:

A) 0.5 L B) L C) 1.5 L D) 2 L E) 3 L

Look at the question logically:

"A train of length L is traveling at a constant velocity and passes a pole in t seconds" To cross a pole (which can be considered a point), why does the train take t secs? Because the whole length of the train has to cross it.

" If the same train travelling at the same velocity passes a platform in 3t seconds" Why does the train take extra 2t secs now? Because of the length of the platform. So the length of the platform must be 2L.

Concentration: General Management, Entrepreneurship

GPA: 3.8

WE: Engineering (Energy and Utilities)

Re: A train of length L is traveling at a constant velocity and passes a [#permalink]

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16 Aug 2017, 11:56

shamikba wrote:

A train of length L is traveling at a constant velocity and passes a pole in t seconds. If the same train travelling at the same velocity passes a platform in 3t seconds then what is the length of the platform:

A) 0.5 L B) L C) 1.5 L D) 2 L E) 3 L

It's a very simple question.. So, Train of length L passes a pole in t seconds. Velocity of pole v= L/t

Now this train of length L passes platform of say length p passes in 3t seconds . So, (L+p)= v (3t) = L/t(3t) 3L -> p = 2L

Concentration: General Management, Entrepreneurship

GPA: 3.8

WE: Engineering (Energy and Utilities)

Re: A train of length L is traveling at a constant velocity and passes a [#permalink]

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16 Aug 2017, 11:59

shamikba wrote:

A train of length L is traveling at a constant velocity and passes a pole in t seconds. If the same train travelling at the same velocity passes a platform in 3t seconds then what is the length of the platform:

A) 0.5 L B) L C) 1.5 L D) 2 L E) 3 L

We can also analyse it and solve it in a very short span of time as VeritasPrepKarishma suggested...

Train of length L passes a pole in t seconds i.e. it covers L in t seconds. So, in 3t seconds it covers 3L distance, out of which L is length of train and 2L is length of platform... very simple, isn't it? :)
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