GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 05 Dec 2019, 07:47

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# A train travels from Albany to Syracuse, a distance of 120 miles, at

Author Message
TAGS:

### Hide Tags

Intern
Status: pursuing a dream
Joined: 02 Jun 2011
Posts: 39
Schools: MIT Sloan (LGO)
A train travels from Albany to Syracuse, a distance of 120 miles, at  [#permalink]

### Show Tags

13 Aug 2011, 07:46
3
00:00

Difficulty:

25% (medium)

Question Stats:

77% (02:04) correct 23% (03:00) wrong based on 244 sessions

### HideShow timer Statistics

A train travels from Albany to Syracuse, a distance of 120 miles, at the average rate of 50 miles per hour. The train then travels back to Albany from Syracuse. The total travelling time of the train is 5 hours and 24 minutes. What was the average rate of speed of the train on the return trip to Albany?

A: 60 mph
B: 50 mph
C: 48 mph
D: 40 mph
E: 35 mph
Retired Moderator
Joined: 20 Dec 2010
Posts: 1547
Re: A train travels from Albany to Syracuse, a distance of 120 miles, at  [#permalink]

### Show Tags

13 Aug 2011, 08:40
1
2
LGOdream wrote:
A train travels from Albany to Syracuse, a distance of 120 miles, at the average rate of 50 miles per hour. The train then travels back to Albany from Syracuse. The total traveling time of the train is 5 hours and 24 minutes. What was the average rate of speed of the train on the return trip to Albany?

A: 60 mph
B: 50 mph
C: 48 mph
D: 40 mph
E: 35 mph

What would be the fastest / most efficient approach? The total travelling time being in hours and minutes is really annoying.

5 hours 24 minutes = $$5+\frac{24}{60}hours=5+\frac{2}{5}hours=\frac{27}{5}hours$$

From Albany to Syracuse,
D=120 miles
t=?
s=50 m/h

t*s=D
t=D/s=120/50=12/5 hours

Thus, time spent coming back = Total time-time spent going from A to S= $$\frac{27}{5}-\frac{12}{5}=\frac{15}{5}=3hours$$

Coming back:
Speed=D/t = 120/3=40 m/h

Ans: "D"
_________________
Senior Manager
Status: Math is psycho-logical
Joined: 07 Apr 2014
Posts: 402
Location: Netherlands
GMAT Date: 02-11-2015
WE: Psychology and Counseling (Other)
Re: A train travels from Albany to Syracuse, a distance of 120 miles, at  [#permalink]

### Show Tags

05 Mar 2015, 16:31
1
99% of the cases I will make the RTD chart:

................R............T..........D
GO...........50.........2.4........120
BACK........40..........3..........120
ALL.......................5.4........240

First we need to note the measurement. So, the question asks for the Rate of BACK, and we are given the initial Rate for GO in miles per hour, so we need the Times to be in hours. So, 5 hours and 24 minutes will be 5.4 hours.

We only need to find how much 24 minutes are in hours, so 24/60 = 2/5 = 0,4. We add this to 5 hours, so total 5.4 hours.

We find the Time for GO like this:
50T=120
T=2.4

Now, we are only missing the time for BACK. We subtract 2.4 from 5.4 and end up with 3.

Finally, R*3=120 --> R = 40. ANS D
Director
Joined: 03 May 2007
Posts: 613
Schools: University of Chicago, Wharton School
Re: A train travels from Albany to Syracuse, a distance of 120 miles, at  [#permalink]

### Show Tags

13 Aug 2011, 18:49
LGOdream wrote:
A train travels from Albany to Syracuse, a distance of 120 miles, at the average rate of 50 miles per hour. The train then travels back to Albany from Syracuse. The total travelling time of the train is 5 hours and 24 minutes. What was the average rate of speed of the train on the return trip to Albany?

A: 60 mph
B: 50 mph
C: 48 mph
D: 40 mph
E: 35 mph

What would be the fastest / most efficient approach? The total travelling time being in hours and minutes is really annoying.

Total time taken 5 hours 24 minuets
Time taken to drive Albany to Syracuse = 120 miles /50 miles = 2 hours 24 minuets (here is a chance of doing 40 minuets instead of 24 minuets. This is a trap.)
Time taken to drive back from Albany to Syracuse = 5 hours 24 minuets - 2 hours 24 minuets = 3 hours

Speed to drive back from Albany to Syracuse = 120 / 3 hours = 40 mph.
Director
Joined: 01 Feb 2011
Posts: 531
Re: A train travels from Albany to Syracuse, a distance of 120 miles, at  [#permalink]

### Show Tags

14 Aug 2011, 11:29
Total time for the round trip = 5 hr 24 min

time taken for A to S trip = 12/5

time taken for S to A trip = 5+(24/60) - 12/5 = 3hr

Speed on the return trip = 120/3 = 40 mph

Senior SC Moderator
Joined: 22 May 2016
Posts: 3724
A train travels from Albany to Syracuse, a distance of 120 miles, at  [#permalink]

### Show Tags

12 Jul 2017, 17:24
LGOdream wrote:
A train travels from Albany to Syracuse, a distance of 120 miles, at the average rate of 50 miles per hour. The train then travels back to Albany from Syracuse. The total travelling time of the train is 5 hours and 24 minutes. What was the average rate of speed of the train on the return trip to Albany?

A: 60 mph
B: 50 mph
C: 48 mph
D: 40 mph
E: 35 mph

Total time - time for Leg1 = time for Leg2 (return)...

...which will yield rate of speed for Leg2.

1. Given: 5 hrs, 24 mins = 5$$\frac{24}{60}$$ = 5$$\frac{4}{10}$$ = 5.4 total time

2. Leg1 time = D/r --> $$\frac{120}{50}$$ = 2.4 hrs

3. Leg2 time = 5.4 - 2.4 = 3 hrs

4.Leg2 rate of speed = D/t = $$\frac{120}{3}$$ = 40 miles per hour

_________________
SC Butler has resumed! Get two SC questions to practice, whose links you can find by date, here.

Never doubt that a small group of thoughtful, committed citizens can change the world; indeed, it's the only thing that ever has -- Margaret Mead
A train travels from Albany to Syracuse, a distance of 120 miles, at   [#permalink] 12 Jul 2017, 17:24
Display posts from previous: Sort by