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26 Jul 2010, 08:39
6
KUDOS
5
This post was
BOOKMARKED
00:00

Difficulty:

65% (hard)

Question Stats:

67% (02:29) correct 33% (02:54) wrong based on 378 sessions

A woman sold 100 oranges at $12.10, some at the rate of 3 for 35 cents and the rest at 7 for 85 cents. How many were sold at the first rate? A. 45 B. 21 C. 9 D. 15 E. 12 [Reveal] Spoiler: OA _________________ If the Q jogged your mind do Kudos me : ) Kudos [?]: 953 [6], given: 22 Manager Joined: 02 Apr 2010 Posts: 102 Kudos [?]: 142 [15], given: 18 Re: Oranges sold at different rates [#permalink] ### Show Tags 26 Jul 2010, 09:58 15 This post received KUDOS 1 This post was BOOKMARKED This can be solved like a classical mixture problem but numbers are awkward to deal with. It's easier to just look at the answer choices. You know that a multiple of 3 oranges has to be sold at the first rate, and a multiple of 7 at the second rate. You simple subtract the answer choices for the first rate from 100 and check whether the remainder (i.e. the number of oranges sold at the second rate) is a multiple of 7. 100 - 45 = 55 => not a multiple of 7 so exclude 100 - 21 = 79 => not a multiple of 7 so exclude 100 -9 = 91 => a multiple of 7 so keep 100 - 15 = 85 => not a multiple of 7 so exclude 100 - 12 = 88 => not a multiple of 7 so exclude Hence, answer choice 9 is correct. Kudos [?]: 142 [15], given: 18 Senior Manager Status: mba here i come! Joined: 07 Aug 2011 Posts: 261 Kudos [?]: 1248 [5], given: 48 Re: Oranges sold at different rates [#permalink] ### Show Tags 29 Feb 2012, 10:03 5 This post received KUDOS $$\frac{35}{3}x+\frac{85}{7}(100-x)=1210$$ solve and you'll get x = 9 _________________ press +1 Kudos to appreciate posts Kudos [?]: 1248 [5], given: 48 Manager Joined: 10 Nov 2010 Posts: 246 Kudos [?]: 412 [0], given: 22 Location: India Concentration: Strategy, Operations GMAT 1: 520 Q42 V19 GMAT 2: 540 Q44 V21 WE: Information Technology (Computer Software) Re: Oranges sold at different rates [#permalink] ### Show Tags 15 Mar 2012, 21:18 $$\frac{35}{3}x+\frac{85}{7}(100-x)=1210$$ Can you pls explain the Right hand side of equation. Won't it be 12.10 _________________ The proof of understanding is the ability to explain it. Kudos [?]: 412 [0], given: 22 Veritas Prep GMAT Instructor Joined: 16 Oct 2010 Posts: 7747 Kudos [?]: 17867 [5], given: 235 Location: Pune, India Re: Oranges sold at different rates [#permalink] ### Show Tags 15 Mar 2012, 22:45 5 This post received KUDOS Expert's post GMATD11 wrote: $$\frac{35}{3}x+\frac{85}{7}(100-x)=1210$$ Can you pls explain the Right hand side of equation. Won't it be 12.10 The equation equates the total selling price. He gets$12.10 i.e. 1210 cents.
If he sold x oranges for 35/3 cents and (100-x) for 85/7 cents, this is a total of
(35/3) * x + (85/7) * (100-x) cents. You equate cents to cents.

Also, you can use the weighted average formula here:

w1/w2 = (85/7 - 121/10)/(121/10 - 35/3) = 9/91

Total 9+91 is 100. So he sells 9 oranges at 35 for 3 and 91 oranges at 85 for 7.
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Get started with Veritas Prep GMAT On Demand for $199 Veritas Prep Reviews Kudos [?]: 17867 [5], given: 235 Intern Joined: 12 Aug 2012 Posts: 6 Kudos [?]: [0], given: 18 Re: Oranges sold at different rates [#permalink] ### Show Tags 17 Aug 2012, 00:47 GMATD11 wrote: $$\frac{35}{3}x+\frac{85}{7}(100-x)=1210$$ Can you pls explain the Right hand side of equation. Won't it be 12.10 Hi, Because we are taking all the values in cents so we have converted$12.10 into cents which is 1210 cents.
as 1 cent =0.01 Dollar

Hope this helps.

Try and fail but never fail to try.

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01 Oct 2013, 05:31
for such question need a will power to take on some random complicated numbers. i derived the equation but goofed up with the numbers
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02 May 2015, 09:14
simple question.... killer calculation.. WOW...

rxs0005 wrote:
A woman sold 100 oranges at $12.10, some at the rate of 3 for 35 cents and the rest at 7 for 85 cents. How many were sold at the first rate? A. 45 B. 21 C. 9 D. 15 E. 12 _________________ Kudos to you, for helping me with some KUDOS. Kudos [?]: 39 [0], given: 113 Non-Human User Joined: 09 Sep 2013 Posts: 15507 Kudos [?]: 283 [0], given: 0 Re: A woman sold 100 oranges at$12.10, some at the rate of 3 [#permalink]

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Re: A woman sold 100 oranges at $12.10, some at the rate of 3 [#permalink] 07 Nov 2016, 05:07 Display posts from previous: Sort by # A woman sold 100 oranges at$12.10, some at the rate of 3

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