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A yellow taxi cab went from Downtown to the Beachside and back at an a

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A yellow taxi cab went from Downtown to the Beachside and back at an a  [#permalink]

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New post 17 Sep 2017, 11:47
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A
B
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Difficulty:

  65% (hard)

Question Stats:

54% (02:29) correct 46% (02:24) wrong based on 74 sessions

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A yellow taxi cab went from Downtown to the Beachside and back at an average speed of 2/3 miles per hour. If the distance from Beachside to Downtown is 1 mile, and the trip back took half as much time as the trip there, what was the average speed of the yellow taxi cab on the way to Beachside?

A 1/3
B 1/2
C 3/4
D 2/3
E 3/2

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Re: A yellow taxi cab went from Downtown to the Beachside and back at an a  [#permalink]

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New post 17 Sep 2017, 19:08
1
SajjadAhmad wrote:
A yellow taxi cab went from Downtown to the Beachside and back at an average speed of 2/3 miles per hour. If the distance from Beachside to Downtown is 1 mile, and the trip back took half as much time as the trip there, what was the average speed of the yellow taxi cab on the way to Beachside?

A 1/3
B 1/2
C 3/4
D 2/3
E 3/2




Hi....

Let the time taken be x while going and therefore\(\frac{x}{2}\) on return trip.
So total time =x+x/2=3x/2..
Distance=1+1=2..
So average speed=2/(3x/2)=4/3x..
So 4/3x=2/3....x=2

Now on the way to beach side..
D=1
Time taken =2 HR
So speed = 1/2

B
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Re: A yellow taxi cab went from Downtown to the Beachside and back at an a  [#permalink]

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New post 22 Sep 2017, 07:56
1
SajjadAhmad wrote:
A yellow taxi cab went from Downtown to the Beachside and back at an average speed of 2/3 miles per hour. If the distance from Beachside to Downtown is 1 mile, and the trip back took half as much time as the trip there, what was the average speed of the yellow taxi cab on the way to Beachside?

A 1/3
B 1/2
C 3/4
D 2/3
E 3/2



We can let the time from Downtown to Beachside = t, and thus the time from Beachside to Downtown = t/2.

Since the average speed was ⅔, we have:

average speed = (total distance)/(total time)

2/3 = (1 + 1)/(t + t/2)

2/3 = 2/(3t/2)

3t = 6

t = 2

Since it takes 2 hours to go from Downtown to Beachside, a distance of 1 mile, the speed is 1/2 mph.

Answer: B
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Re: A yellow taxi cab went from Downtown to the Beachside and back at an a  [#permalink]

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New post 02 Jun 2019, 22:04
chetan2u wrote:
SajjadAhmad wrote:
A yellow taxi cab went from Downtown to the Beachside and back at an average speed of 2/3 miles per hour. If the distance from Beachside to Downtown is 1 mile, and the trip back took half as much time as the trip there, what was the average speed of the yellow taxi cab on the way to Beachside?

A 1/3
B 1/2
C 3/4
D 2/3
E 3/2




Hi....

Let the time taken be x while going and therefore\(\frac{x}{2}\) on return trip.
So total time =x+x/2=3x/2..
Distance=1+1=2..
So average speed=2/(3x/2)=4/3x..
So 4/3x=2/3....x=2

Now on the way to beach side..
D=1
Time taken =2 HR
So speed = 1/2

B

Bunuel Doesn't "the trip back took half as much time as the trip there" mean time for return trip is half of time taken for full trip??
So equal time for to and fro journey and average speed is 2/3 mph

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Re: A yellow taxi cab went from Downtown to the Beachside and back at an a   [#permalink] 02 Jun 2019, 22:04
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