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ABCD is a rhombus with the diagonals AC and BD intersecting at the ori

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ABCD is a rhombus with the diagonals AC and BD intersecting at the ori  [#permalink]

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New post 06 Mar 2019, 07:21
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A
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E

Difficulty:

  55% (hard)

Question Stats:

53% (01:51) correct 47% (01:44) wrong based on 36 sessions

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ABCD is a rhombus with the diagonals AC and BD intersecting at the origin on the x-y plane. The equation of the straight line AD is x + y = 1. What is the equation of BC?

A) x + y = −1
B) x − y = −1
C) x + y = 1
D) y − x = −1
E) None of these.
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Re: ABCD is a rhombus with the diagonals AC and BD intersecting at the ori  [#permalink]

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New post 19 Mar 2019, 11:55
mangamma wrote:
ABCD is a rhombus with the diagonals AC and BD intersecting at the origin on the x-y plane. The equation of the straight line AD is x + y = 1. What is the equation of BC?

A) x + y = −1
B) x − y = −1
C) x + y = 1
D) y − x = −1
E) None of these.


plug in values and test
we see for x+y=-1
we get values of x,y at 1st and 4th quadrant
IMO A
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Re: ABCD is a rhombus with the diagonals AC and BD intersecting at the ori   [#permalink] 19 Mar 2019, 11:55
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ABCD is a rhombus with the diagonals AC and BD intersecting at the ori

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