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Manager
Joined: 12 Apr 2006
Posts: 213

Kudos [?]: 30 [0], given: 17

Location: India

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24 Jun 2006, 21:22
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Kudos [?]: 30 [0], given: 17

Manager
Joined: 12 Feb 2006
Posts: 115

Kudos [?]: 80 [0], given: 0

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24 Jun 2006, 21:48
I am getting C simply by multiply 16 x 360 and 18 x 360.

Is this the OA?

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Director
Joined: 16 Aug 2005
Posts: 937

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Location: France

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25 Jun 2006, 16:41
(1) 16 feet/s = 10.9 mi/hr
So, distance travelled in 1/2 hr = 5.45miles

since speed was greater than 16 feet/s, distance travelled was > 5.45 miles - not sufficient

(2) 18 feet/s = 12.3 mi/hr
So, distance travelled in 1/2 hr = 6.15 miles

since speed was less than 18 feet/s, distance travelled was < 6.15 miles - not sufficient

Taking together: 5.45 < distance < 6.15

Hence E
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I believe its yogurt!

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Manager
Joined: 09 Apr 2006
Posts: 173

Kudos [?]: 3 [0], given: 0

Location: Somewhere in Wisconsin!

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25 Jun 2006, 22:12
Good explanation. We don't get any distinct value from I and II. Combining the two results we get 28800 < d < 32400 (in feet). We need to know whether d = 31680 feet? (d = distance covered in 1/2 an hour). So E.
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Thanks,
Zooroopa

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Intern
Joined: 04 May 2006
Posts: 49

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26 Jun 2006, 00:53
Quote:
Good explanation. We don't get any distinct value from I and II. Combining the two results we get 28800 < d < 32400 (in feet). We need to know whether d = 31680 feet? (d = distance covered in 1/2 an hour). So E.

Did the same way. I vote for E too.

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Albert Einstein

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Manager
Joined: 22 May 2006
Posts: 71

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26 Jun 2006, 02:38
A,B and D can be easily ruled out.
C can be ruled out because the speed can be any value from 16.1 to 17.9
hence different answers for different values...

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26 Jun 2006, 02:38
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