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Adam, Ben, and Charles take an exam, and their average is p points. D

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Adam, Ben, and Charles take an exam, and their average is p points. D  [#permalink]

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New post 25 Nov 2019, 00:53
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[GMAT math practice question]

Adam, Ben, and Charles take an exam, and their average is \(p\) points. David takes the same exam and gets s points. The average of these \(4\) students is \(x\) points less than \(p\) points. What is the value of \(s\), in terms of \(p\) and \(x\)?

A. \(2p-x \)

B. \(3p-2x\)

C. \(p-4x \)

D. \(p-x\)

E. \(4p-3x\)

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Adam, Ben, and Charles take an exam, and their average is p points. D  [#permalink]

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New post 25 Nov 2019, 09:23
MathRevolution wrote:
[GMAT math practice question]

Adam, Ben, and Charles take an exam, and their average is \(p\) points. David takes the same exam and gets s points. The average of these \(4\) students is \(x\) points less than \(p\) points. What is the value of \(s\), in terms of \(p\) and \(x\)?

A. \(2p-x \)

B. \(3p-2x\)

C. \(p-4x \)

D. \(p-x\)

E. \(4p-3x\)

So total of all three \(a+ b+c= 3p\) then \(d\) get \(s\) points . So now the total of all four \( a+b+c + d = 3p +s\)
Given avg.of four = \(\frac{3p +s}{4} =p-x\)
\(3p+s=4p-4x\)
\(s=p-4x\)

Ans- C
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Re: Adam, Ben, and Charles take an exam, and their average is p points. D  [#permalink]

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New post 27 Nov 2019, 04:29
=>

Assume \(a, b,\) and \(c\) are the scores of Adam, Ben, and Chares, respectively.

Then we have \(p = \frac{(a + b + c)}{3}\) or \(a + b + c = 3p.\)

The average of the 4\(\) people including David is \(\frac{(a + b + c + s)}{4} = \frac{(3p + s)}{4} = p-x.\)

Then we have \(4p - 4x = 3p + s\) or \(s = p - 4x.\)

Therefore, C is the answer.
Answer: C
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Re: Adam, Ben, and Charles take an exam, and their average is p points. D   [#permalink] 27 Nov 2019, 04:29
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Adam, Ben, and Charles take an exam, and their average is p points. D

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