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Re: Adam completes 60% of a task in 15 days and then takes the help of Bob [#permalink]
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Adam completes rest of the work in 10 days.
0.6/15 =0.4/?, ?=10
So he completes 1/10 of work in one day.
Bob=1/2 *1/10=1/20
Carol=1/2 *1/20=1/40

(1/10+ 1/20+ 1/40)*X=1
X=40/7 = 5 5/7
Option C

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Re: Adam completes 60% of a task in 15 days and then takes the help of Bob [#permalink]
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DisciplinedPrep wrote:
Adam completes 60% of a task in 15 days and then takes the help of Bob and Carol. Bob is 50% as efficient as Adam is and Carol is 50% as efficient as Bob is. In how many more days will they complete the task?

A. \(13\frac{1}{3}\) days

B. \(8\frac{2}{3}\) days

C. \(5\frac{5}{7}\) days

D. \(7\frac{5}{7}\) days

E. 5 days


60 % work is completed in 15 days...

So, 100% work is completed in \(\frac{15*100}{60}\) = 25 days

Let the total work be 100 units !!

SO, Efficiency of A is 4 units/day , Wfficiency of B is 2 Units/day & Efficiency of C is 1 Unit/day

Combined efficiency of A, B and C is 7 Units/day

So, Time taken to complete remainit 40 Units work is 40/7 , Anser must be (C) \(5\frac{5}{7}\) days

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