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# After eating half of the chocolate mini bars in a can

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Manager
Joined: 25 Jun 2012
Posts: 65
Followers: 0

Kudos [?]: 55 [0], given: 21

After eating half of the chocolate mini bars in a can [#permalink]

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30 Oct 2012, 22:53
00:00

Difficulty:

5% (low)

Question Stats:

86% (02:12) correct 14% (01:28) wrong based on 83 sessions

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After eating half of the chocolate mini bars in a can, Clayton gave one fourth of the remaining mini bar chocolates to his buddy and realized that he only had 6 chocolate mini bars left. How many mini bar chocolates did he originally have?

(A) 2
(B) 4
(C) 8
(D) 16
(E) 18
[Reveal] Spoiler: OA

Last edited by Bunuel on 30 Oct 2012, 23:14, edited 1 time in total.
Edited the tags.
Math Expert
Joined: 02 Sep 2009
Posts: 38908
Followers: 7739

Kudos [?]: 106246 [0], given: 11618

Re: After eating half of the chocolate mini bars in a can [#permalink]

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30 Oct 2012, 23:19
After eating half of the chocolate mini bars in a can, Clayton gave one fourth of the remaining mini bar chocolates to his buddy and realized that he only had 6 chocolate mini bars left. How many mini bar chocolates did he originally have?

(A) 2
(B) 4
(C) 8
(D) 16
(E) 18

Say Clayton originally had $$x$$ bars. He ate half, thus he was left with $$\frac{x}{2}$$ bars. Then, he gave $$\frac{x}{8}$$ bars (one fourth of the remaining) to his friend.

Given that $$\frac{x}{2}-\frac{x}{8}=6$$ --> $$x=16$$.

Hope it's clear.
_________________
Manager
Joined: 25 Jun 2012
Posts: 65
Followers: 0

Kudos [?]: 55 [0], given: 21

Re: After eating half of the chocolate mini bars in a can [#permalink]

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31 Oct 2012, 12:34
Bunuel wrote:

Given that $$\frac{x}{2}-\frac{x}{8}=6$$ --> $$x=16$$.

Hope it's clear.

Just great, I was told lengthy solution
Re: After eating half of the chocolate mini bars in a can   [#permalink] 31 Oct 2012, 12:34
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