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# Allen travelled in a car and David travelled in a train. If

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Intern
Joined: 31 May 2006
Posts: 44

Kudos [?]: 11 [0], given: 0

Allen travelled in a car and David travelled in a train. If [#permalink]

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22 Jul 2006, 15:58
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Allen travelled in a car and David travelled in a train. If Allen and David travelled the same length of time and Allen travelled 108 miles, how many miles did David travel?

i) Allen's average speed was 3/5 of David's average speed.
ii) Allen and David each travelled 3 hours.

Kudos [?]: 11 [0], given: 0

Director
Joined: 06 May 2006
Posts: 790

Kudos [?]: 40 [0], given: 2

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22 Jul 2006, 16:03
A?

#1. Since we know the time travelled is the same and ratios of average speed, we know distance travelled by David.

#2. Not sufficient.
_________________

Uh uh. I know what you're thinking. "Is the answer A, B, C, D or E?" Well to tell you the truth in all this excitement I kinda lost track myself. But you've gotta ask yourself one question: "Do I feel lucky?" Well, do ya, punk?

Kudos [?]: 40 [0], given: 2

CEO
Joined: 20 Nov 2005
Posts: 2892

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Schools: Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008

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23 Jul 2006, 01:42
Straight A

108/A = x/D
St1: A = 3D/5
108/(3D/5) = x/D
x = 180
_________________

SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

Kudos [?]: 336 [0], given: 0

SVP
Joined: 30 Mar 2006
Posts: 1728

Kudos [?]: 102 [0], given: 0

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26 Jul 2006, 03:37
A

1) Let time be t. Distance travelled by David be x

Hence
108/t = 3/5 * x/t
X = 108*5/3

Suff

2) we know the time David travelled. No idea about speed. Hence Not suff

Kudos [?]: 102 [0], given: 0

Manager
Joined: 14 Mar 2006
Posts: 208

Kudos [?]: 10 [0], given: 0

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26 Jul 2006, 08:49
A aswell.

from stmt 1) we know the ratio of the avg speed, and since the time is the same we can solve.
from stmt2) we are given the time, but we still don't know the avg speed for david.

Kudos [?]: 10 [0], given: 0

VP
Joined: 02 Jun 2006
Posts: 1257

Kudos [?]: 108 [0], given: 0

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26 Jul 2006, 09:22
Let
Ta = Allen's travel time
Td = David's travel time
Sa = Allen's average speed
Sd = David's average speed
Da = Allen's distance
Dd = David's distance

Given Ta = Td, Da= 108

Dist = speed x time
Dd = Sd x Td = Sd x Ta = Sdx 108/Sa

Dd = 108 x (Sd/Sa)

S1: Given Sa/Sd = 3/5
Sufficient to compute Dd.

S2: Ta = Td = 3 hrs.

Not sufficient.

Kudos [?]: 108 [0], given: 0

26 Jul 2006, 09:22
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