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An activist club is advocating against the opening of Walmart

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firas92
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An activist club is advocating against the opening of Walmart [#permalink] New post   Updated on: 19 Jun 2019, 09:59
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An activist club is advocating against the opening of Walmart in a city and has decided to go to the Mayor's office every day. The secretary of the club has proposed taking exactly 4 people with him every day. If the secretary goes with a different group of people every day, including weekends and holidays, how many days can he go without repeating a group?

1. The club has 10 members.

2. Every day, the secretary does not take exactly 5 members of the club with him.
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D

Originally posted by firas92 on 19 Jun 2019, 07:22.
Last edited by firas92 on 19 Jun 2019, 09:59, edited 1 time in total.
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IanStewart
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Re: An activist club is advocating against the opening of Walmart [#permalink] New post   19 Jun 2019, 09:46
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If you know how many people you have, you can answer any question about the number of ways to pick various types of groups from those people. Since each statement tells us we have 10 people, the answer is D.
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anchalnarula1995
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Re: An activist club is advocating against the opening of Walmart [#permalink] New post   19 Jun 2019, 11:30
firas92 wrote:
An activist club is advocating against the opening of Walmart in a city and has decided to go to the Mayor's office every day. The secretary of the club has proposed taking exactly 4 people with him every day. If the secretary goes with a different group of people every day, including weekends and holidays, how many days can he go without repeating a group?

1. The club has 10 members.

2. Every day, the secretary does not take exactly 5 members of the club with him.


How does the second statement tell us that the club has 10 members?
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An activist club is advocating against the opening of Walmart [#permalink] New post   19 Jun 2019, 11:38
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Secreatry+ 4 people that goes with him+ 5 people that are left at club= 10

anchalnarula1995 wrote:
firas92 wrote:
An activist club is advocating against the opening of Walmart in a city and has decided to go to the Mayor's office every day. The secretary of the club has proposed taking exactly 4 people with him every day. If the secretary goes with a different group of people every day, including weekends and holidays, how many days can he go without repeating a group?

1. The club has 10 members.

2. Every day, the secretary does not take exactly 5 members of the club with him.


How does the second statement tell us that the club has 10 members?


Posted from my mobile device
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menonrit
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Re: An activist club is advocating against the opening of Walmart [#permalink] New post   24 Jun 2019, 03:02
firas92 wrote:
An activist club is advocating against the opening of Walmart in a city and has decided to go to the Mayor's office every day. The secretary of the club has proposed taking exactly 4 people with him every day. If the secretary goes with a different group of people every day, including weekends and holidays, how many days can he go without repeating a group?

1. The club has 10 members.

2. Every day, the secretary does not take exactly 5 members of the club with him.




Hi,

could you please explain why D is the answer.
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aliakberza
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Re: An activist club is advocating against the opening of Walmart [#permalink] New post   28 Jun 2019, 04:50
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menonrit wrote:
firas92 wrote:
An activist club is advocating against the opening of Walmart in a city and has decided to go to the Mayor's office every day. The secretary of the club has proposed taking exactly 4 people with him every day. If the secretary goes with a different group of people every day, including weekends and holidays, how many days can he go without repeating a group?

1. The club has 10 members.


2. Every day, the secretary does not take exactly 5 members of the club with him.




Hi,

could you please explain why D is the answer.


menonrit

Its a bit confusing and awkwardly worded. But i believe that is by design to confuse you in to selecting A as the answer. I fell for it too! But if you re-read ST-2 :

firas92 wrote:
2. Every day, the secretary does not take exactly 5 members of the club with him.


In other words, every day, 5 people are left behind at the club and not taken to the protest. If including the secretary there are 5 people at the protest and 5 are left behind, this is the same info as st-1 and hence sufficient.

Hope it helps. :)
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Re: An activist club is advocating against the opening of Walmart [#permalink] New post   12 Nov 2019, 10:37
Nice question, esp B option
It states that secretary does nto take 5 with him and question already mentioned he takes 4 with him so it mean 5 (he left ) + 4 he takes and 1 (himself) = 10 ppl
which means club has 10 members.
Reduces to Stmt A
which is suffcient
thus D
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Re: An activist club is advocating against the opening of Walmart [#permalink] New post   18 Nov 2019, 20:44
How will we solve it if it is a PS question
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Re: An activist club is advocating against the opening of Walmart [#permalink] New post   22 Nov 2019, 04:53
IanStewart wrote:
If you know how many people you have, you can answer any question about the number of ways to pick various types of groups from those people. Since each statement tells us we have 10 people, the answer is D.


How do we solve this question though?? Bunuel

Posted from my mobile device
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An activist club is advocating against the opening of Walmart [#permalink] New post   22 Nov 2019, 09:29
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ya,
We can easily understand statement A is sufficient.

Now comes to statement B, that is language , by this test maker is trying to confuse.

here is each day exactly 5 members he did not take with him.

That mean club has n members.

He does not take member = 5 , and he is with n-5 member.
but we know 1+4 = n-5
Hence n-5 = 5
n= 10 members.

rest you know story.

Hence B is also sufficient.

Answer is D.
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Re: An activist club is advocating against the opening of Walmart [#permalink] New post   22 Nov 2019, 21:18
To propose and to do are two different things. JS
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Re: An activist club is advocating against the opening of Walmart [#permalink] New post   22 Nov 2019, 21:27
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LJ11 wrote:
How will we solve it if it is a PS question


Then it will be given that there are total 10 members in the activist club including secretary.

Number of different 4 people groups = 9C4 = 126

Hope it solves your query
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Re: An activist club is advocating against the opening of Walmart [#permalink] New post   10 Dec 2022, 04:23
In Statement (A), it is not explicitly mentioned that the secretary is one of the 10 members, while this can be understood from statement (B). So, should the answer not be (B)?
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Re: An activist club is advocating against the opening of Walmart [#permalink] New post   12 Aug 2023, 21:06
JiddiHuMain wrote:
ya,
We can easily understand statement A is sufficient.

Now comes to statement B, that is language , by this test maker is trying to confuse.

here is each day exactly 5 members he did not take with him.

That mean club has n members.

He does not take member = 5 , and he is with n-5 member.
but we know 1+4 = n-5
Hence n-5 = 5
n= 10 members.

rest you know story.

Hence B is also sufficient.

Answer is D.


Can you please explain this? "1+4 = n-5"
Shouldn't it be 4 = n+5
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Re: An activist club is advocating against the opening of Walmart [#permalink]
12 Aug 2023, 21:06
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