cyberjadugar wrote:
An ant crawls from one corner of a room to the diagonally opposite corner along the shortest possible path. If the dimensions of the room are 3 x 3 x 3, what distance does the ant cover?
A. \(3\sqrt{2}+3\)
B. \(6\sqrt{2}\)
C. \(3*3^{\frac 13}\)
D. \(3\sqrt{5}\)
E. \(9\)
Hi
Bunuel,
chetan2uIf the ant has to reach opposite corner of a room diagonally, shouldn't the answer be \(3\sqrt{3}\). can you please let me know where I am wrong in the below approach.
First the ant will crawl along the diagonal of one plane i.e. \(3\sqrt{2}\) and the then along the edge to the opposite corner = 3
So the total diagonal length will be \(d^2 = 3^2 + (3\sqrt{2})^2\) = \(27\)
Hi..
I'll attach a figure in sometime, but just try to understand..
Take any two adjacent sides which are perpendicular to each other and sides of each are 3*3...ABCD and BDEF are two sides
Now open it ...
A.....B......E
C.....D......F
The ant has to move from C to E..
By opening the two sides you have a rectangle ACFE..
The diagonal CE will be the shortest route..
CE=√(3^2+6^2)=√45=3√5
Hope you could visualise
.. Thanks for the explanation.. Yes I could visualize it. However, the question never mentions that ant can walk only along the plane. It can take the edge path also. For Ex - it will move from one of Diagonal of ABCD and then the adjoining edge - In this case 3root(2) + 3.
Please correct if I am missing something.