An engagement team consists of a project manager, team leader, and

Hi TheMastermind ,

When I am saying two consultants are always together, that means I already have them on my bucket and now I have to select the pending 2 from the remaining 5 consultants. Thus, we are using 5C2

Let me know if you need the detailed explanation for this question.

Should total up to 60 vice 40.

How do we get 5C2 when we calculate the total number of combinations when consultants are together?

I understand the explanations given above. I want to understand where i m going wrong with my approach.

So, the team need to have 1 PM, 1 TL and 4 Cs. We have 2 PMs, 3 TLs and 7Cs. Of the 7Cs, 2 wont work together.

# of ways in which 1 PM can be chosen: 2 [2C1]

# of ways in which 1 TL can be chosen: 3 [3c1]

# of ways 4 Cs can be chosen: # of ways 5 Cs with no issues can be chosen + # of ways 6 Cs (5 Cs with no issues + 1 of the 2 Cs with issues) can be chosen * 2 (since either 1 of the 2 Cs having issues can be chosen)

--> 5C4 + 6C4*2 = 35

I understand that 35 is also 7C4. However, I am not able to understand how 5C4 + 6C4*2 includes the cases in which the 2 consultants having issues are put in the same team.

Bunuel, It would be very helpful if you could point out where the flaw in my reasoning is. Thanks in advance

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