Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 30 May 2017, 01:31

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

An integer n, when divided by 3 has a remainder of 2

Author Message
Senior Manager
Joined: 11 Feb 2007
Posts: 351
Followers: 1

Kudos [?]: 139 [0], given: 0

An integer n, when divided by 3 has a remainder of 2 [#permalink]

Show Tags

20 Mar 2007, 00:41
00:00

Difficulty:

(N/A)

Question Stats:

100% (01:45) correct 0% (00:00) wrong based on 8 sessions

HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

An integer n, when divided by 3 has a remainder of 2. An integer t, when divided by 5, has a remainder of 3. What is the remainder when n*t is divided by 15?

(1) n-2 is divisible by 5
(2) t is divisible by 3

OPEN DISCUSSION OF THIS QUESTION IS HERE: when-positive-integer-n-is-divided-by-3-the-remainder-is-86155.html

Last edited by ricokevin on 20 Mar 2007, 01:19, edited 1 time in total.
Senior Manager
Joined: 20 Feb 2007
Posts: 256
Followers: 1

Kudos [?]: 54 [0], given: 0

Show Tags

20 Mar 2007, 01:09

I could find some method but not quick enough...

Last edited by Summer3 on 20 Mar 2007, 01:21, edited 1 time in total.
Senior Manager
Joined: 11 Feb 2007
Posts: 351
Followers: 1

Kudos [?]: 139 [0], given: 0

Show Tags

20 Mar 2007, 01:18
Summer3 wrote:

I have added the OA. Highlight to see.
Senior Manager
Joined: 20 Feb 2007
Posts: 256
Followers: 1

Kudos [?]: 54 [0], given: 0

Show Tags

20 Mar 2007, 01:29
Yeah, first I did it wrong way...so I got wrong answer but I did it again and got C.

This is what I did:

n = 3q + 2 (q = quotient) then I drew a table (i) for q and n...
t = 5q + 3 again I drew a table(ii) for q and t too

(1) (n-2 / 5) = int ....I checked from the table (i) and found n = 17 fit here..
but from table (ii) any value of t can be taken and remainder will be different..INSUFF

(2) t/3 = int .....from table (ii) t = 18 fits here...but n from table (i) can be any value so different remainders...INSUFF

Taking both (1) and (2) together:
n = 17 and t = 18......we can get the answer...SUFF
Senior Manager
Joined: 20 Feb 2007
Posts: 256
Followers: 1

Kudos [?]: 54 [0], given: 0

Show Tags

20 Mar 2007, 01:39
And yes, I rechecked the C by taking another value for n and t, too...e.g. n = 32 from table (i) and t = 63 or even same 18....remainder was same
20 Mar 2007, 01:39
Display posts from previous: Sort by