Bunuel wrote:
Andrew has a certain number of coins in his pocket. He has three times as many dimes as quarters and six times as many nickels as dimes. A nickel is worth $0.05, a dime is worth $0.10 and a quarter is worth $0.25. If he has a total of $10.15, then which of the following represents the number of dimes in Andrew’s pocket?
A. 9
B. 10
C. 18
D. 20
E. 21
We can let q = number of quarters; thus, there are 3q dimes and 6(3q) = 18q nickels. We can create the equation for the value of the coins:
0.05(18q) + 0.10(3q) + 0.25q = 10.15
Multiplying the equation by 100, we have:
5(18q) + 10(3q) + 25q = 1015
90q + 30q + 25q = 1015
145q = 1015
q = 7
Since there are three times as many dimes as quarters, there are 3(7) = 21 dimes.
Answer: E
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