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# Andrew has a certain number of coins in his pocket. He has three times

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Math Expert
Joined: 02 Sep 2009
Posts: 58142
Andrew has a certain number of coins in his pocket. He has three times  [#permalink]

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21 Jul 2016, 23:36
00:00

Difficulty:

55% (hard)

Question Stats:

69% (03:02) correct 31% (02:40) wrong based on 86 sessions

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Andrew has a certain number of coins in his pocket. He has three times as many dimes as quarters and six times as many nickels as dimes. A nickel is worth \$0.05, a dime is worth \$0.10 and a quarter is worth \$0.25. If he has a total of \$10.15, then which of the following represents the number of dimes in Andrew’s pocket?

A. 9
B. 10
C. 18
D. 20
E. 21

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Joined: 15 Jun 2015
Posts: 8
Re: Andrew has a certain number of coins in his pocket. He has three times  [#permalink]

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22 Jul 2016, 00:29
E.
Let number of quarters be q. Therefore , dimes are 3q and nickels are 18q.
Total value = 18q(.05) + 3q(0.1) + .25q =1.45q
Given total value = 10.15
therefore, 1.45q=10.15 or q=7
Number of dimes = 3q or 21
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Joined: 11 Nov 2014
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Re: Andrew has a certain number of coins in his pocket. He has three times  [#permalink]

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22 Jul 2016, 08:49
sarth90 wrote:
E.
Let number of quarters be q. Therefore , dimes are 3q and nickels are 18q.
Total value = 18q(.05) + 3q(0.1) + .25q =1.45q
Given total value = 10.15
therefore, 1.45q=10.15 or q=7
Number of dimes = 3q or 21

shouldn't it be other way round?
three times as many dimes as quarters and six times as many nickels as dimes

n:6d:18q?
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Re: Andrew has a certain number of coins in his pocket. He has three times  [#permalink]

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02 Oct 2018, 19:26
Bunuel wrote:
Andrew has a certain number of coins in his pocket. He has three times as many dimes as quarters and six times as many nickels as dimes. A nickel is worth \$0.05, a dime is worth \$0.10 and a quarter is worth \$0.25. If he has a total of \$10.15, then which of the following represents the number of dimes in Andrew’s pocket?

A. 9
B. 10
C. 18
D. 20
E. 21

We can let q = number of quarters; thus, there are 3q dimes and 6(3q) = 18q nickels. We can create the equation for the value of the coins:

0.05(18q) + 0.10(3q) + 0.25q = 10.15

Multiplying the equation by 100, we have:

5(18q) + 10(3q) + 25q = 1015

90q + 30q + 25q = 1015

145q = 1015

q = 7

Since there are three times as many dimes as quarters, there are 3(7) = 21 dimes.

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Re: Andrew has a certain number of coins in his pocket. He has three times   [#permalink] 02 Oct 2018, 19:26
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