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# Another Probability question

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Manager
Joined: 28 Jul 2004
Posts: 136
Location: Melbourne
Schools: Yale SOM, Tuck, Ross, IESE, HEC, Johnson, Booth
Followers: 1

Kudos [?]: 63 [0], given: 2

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29 Aug 2010, 09:26
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HI, is there a simple way to solve the question below:

What is the probability of getting at least one heart in a 5-card hand dealt from a standard 52-card deck?

My approach was to calculate it as:

At least 1 heart = 1 - No Hearts, which implies

At least 1 heart = 1 -39/52 x 36/51 x 35/50 x 34/49 x 33/48

any simpler approach?

Thanks
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kris

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Joined: 25 Jun 2010
Posts: 91
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Kudos [?]: 37 [0], given: 0

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29 Aug 2010, 09:53
I guess that is the simplest approach for the question asking for "at least" xxxx

At least 1 heart = 1 -39/52 x 38/51 x 37/50 x 36/49 x 35/48

Thanks
Manager
Joined: 28 Jul 2004
Posts: 136
Location: Melbourne
Schools: Yale SOM, Tuck, Ross, IESE, HEC, Johnson, Booth
Followers: 1

Kudos [?]: 63 [0], given: 2

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29 Aug 2010, 10:05
yeh, I moved to 36 from 39

anyway thanks.
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kris

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Joined: 09 Jun 2010
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Kudos [?]: 124 [0], given: 1

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30 Aug 2010, 09:11
Hi krishan,

We can use this approach:

At least 1 heart = 1 -P (No Hearts) = 1- (39C5/52C5)

Will give same result.
Manager
Joined: 16 Feb 2010
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30 Aug 2010, 16:43
krishan wrote:
HI, is there a simple way to solve the question below:

What is the probability of getting at least one heart in a 5-card hand dealt from a standard 52-card deck?

My approach was to calculate it as:

At least 1 heart = 1 - No Hearts, which implies

At least 1 heart = 1 -39/52 x 36/51 x 35/50 x 34/49 x 33/48

any simpler approach?

Thanks

there isn't a simpler one!!

'at least 1' questions are best solve with the 1-no approach
Re: Another Probability question   [#permalink] 30 Aug 2010, 16:43
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