It is currently 18 Nov 2017, 09:21

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Anthony and Michael sit on the six-member board of directors

Author Message
Intern
Joined: 23 Jun 2005
Posts: 24

Kudos [?]: 8 [0], given: 0

Anthony and Michael sit on the six-member board of directors [#permalink]

### Show Tags

14 Aug 2006, 20:52
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Anthony and Michael sit on the six-member board of directors for company X. If the board is to be split up into 2 three-person subcommittees, what percent of all the possible subcommittees that include Michael also include Anthony?

a) 20%
b) 30%
c) 40%
d) 50%
e) 60%

I dont get the explanation at all. Can someone explain this better?

Kudos [?]: 8 [0], given: 0

CEO
Joined: 20 Nov 2005
Posts: 2892

Kudos [?]: 334 [0], given: 0

Schools: Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008

### Show Tags

14 Aug 2006, 22:14
Total subcommittees = 6C3 = 20

Subcommittees that include michael = 5C2 = 10
Subcommittees that include both = 4C1 = 4

_________________

SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

Kudos [?]: 334 [0], given: 0

CEO
Joined: 20 Nov 2005
Posts: 2892

Kudos [?]: 334 [0], given: 0

Schools: Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008

### Show Tags

16 Aug 2006, 10:17
GK_Gmat wrote:
ps_dahiya wrote:
Total subcommittees = 6C3 = 20

Subcommittees that include michael = 5C2 = 10 --> How? Please explain
Subcommittees that include both = 4C1 = 4 --> How? Please explain

If Michael is selected then we need to select two people out of 5. So its 5C2

If Michael and Anthony are selected then we need to select one more person out of 4 people. So its 4C1

Hoep this helps.
_________________

SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

Kudos [?]: 334 [0], given: 0

Director
Joined: 09 Aug 2006
Posts: 754

Kudos [?]: 260 [0], given: 0

### Show Tags

18 Aug 2006, 11:43
ps_dahiya wrote:
GK_Gmat wrote:
ps_dahiya wrote:
Total subcommittees = 6C3 = 20

Subcommittees that include michael = 5C2 = 10 --> How? Please explain
Subcommittees that include both = 4C1 = 4 --> How? Please explain

If Michael is selected then we need to select two people out of 5. So its 5C2

If Michael and Anthony are selected then we need to select one more person out of 4 people. So its 4C1

Hoep this helps.

Great. Thanks a lot.

Kudos [?]: 260 [0], given: 0

Intern
Joined: 09 Aug 2006
Posts: 6

Kudos [?]: 18 [0], given: 0

### Show Tags

18 Aug 2006, 12:14
I think another way to solve it is like this:

The probability for both Michael and Anthony to be selected to the first subcomittee is:
2/6 * (1/5) * (3C2) = 1/5

The total probability for both of them to be selected to either the first or second subcomittee is:
1/5*2 = 2/5 = 40%

Kudos [?]: 18 [0], given: 0

18 Aug 2006, 12:14
Display posts from previous: Sort by

# Anthony and Michael sit on the six-member board of directors

Moderator: chetan2u

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.