It is currently 18 Nov 2017, 12:47

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Anthony and Michael sit on the six-member board of directors

Author Message
Senior Manager
Joined: 05 Mar 2006
Posts: 348

Kudos [?]: 13 [0], given: 0

Anthony and Michael sit on the six-member board of directors [#permalink]

### Show Tags

16 Aug 2006, 11:51
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Anthony and Michael sit on the six-member board of directors for company X. If the board is to be split up into 2 three-person subcommittees, what percent of all the possible subcommittees that include Michael also include Anthony?

20%
30%
40%
50%
60%

Kudos [?]: 13 [0], given: 0

Director
Joined: 06 May 2006
Posts: 790

Kudos [?]: 40 [0], given: 2

### Show Tags

16 Aug 2006, 14:08
A) 20%

The number of ways that Michael and Anthony will be in one 3-member group is the number of ways the other 3-member group can be formed without either of them.

So we have 4 choices, and the number of groups that can be formed is ( 4*3*2). Th total number of ways a group of 3 can be formed is (6*5*4). Probability = 1/5.
_________________

Uh uh. I know what you're thinking. "Is the answer A, B, C, D or E?" Well to tell you the truth in all this excitement I kinda lost track myself. But you've gotta ask yourself one question: "Do I feel lucky?" Well, do ya, punk?

Kudos [?]: 40 [0], given: 2

Manager
Joined: 09 Jul 2006
Posts: 85

Kudos [?]: 1 [0], given: 0

Location: India

### Show Tags

16 Aug 2006, 21:56
Th total number of ways a group of 3 can be formed is (6*5*4). Probability = 1/5.

Paddyboy, I beg to differ with you.
The order of members within the group is not significant. Thus, the number of 3 member groups that can be formed will be 6C3 = 20 and not 6P3.
Also, if Anthony and Michael are to come in 1 group together, the number of groups that can be formed are 5C3 = 5C2 = 10.
Hence, %age = 10/20 = 50%.

Am very weak in probability and permutation-combinations. So kindly let me know if there is an issue with my approach to this problem.
_________________

Cheers!
Prashrash.

Kudos [?]: 1 [0], given: 0

CEO
Joined: 20 Nov 2005
Posts: 2892

Kudos [?]: 334 [0], given: 0

Schools: Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008

### Show Tags

16 Aug 2006, 21:59
Popular one.

see my explanation
http://www.gmatclub.com/phpbb/viewtopic.php?t=33483
_________________

SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

Kudos [?]: 334 [0], given: 0

16 Aug 2006, 21:59
Display posts from previous: Sort by

# Anthony and Michael sit on the six-member board of directors

Moderator: chetan2u

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.