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# Anyone know how to do this

Author Message
Director
Joined: 20 Feb 2008
Posts: 797
Location: Texas
Schools: Kellogg Class of 2011
Anyone know how to do this [#permalink]

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10 May 2008, 17:36
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Anyone know how to do this?
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GMAT Prep #7.GIF [ 8.85 KiB | Viewed 775 times ]

Last edited by jb32 on 10 May 2008, 19:04, edited 2 times in total.
Director
Joined: 23 Sep 2007
Posts: 782

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10 May 2008, 18:21
C

you can just upload the picture instead of putting it in a word document.
Director
Joined: 23 Sep 2007
Posts: 782

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10 May 2008, 20:25
the picture that you have on now is not the same as the picture in your original question.

(2^x) - (2^(x-2)) ---> ((2^x) * 1) - ((2^x) * (2^-2))

(2^x) (1 - (2^-2))

(2^x) (3/4) = 3(2^13)

2^x = 2^15

x = 15
Senior Manager
Joined: 07 Jan 2008
Posts: 399

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10 May 2008, 22:21
jbpayne wrote:
Anyone know how to do this?

Take 2^(x-2) out then you have the answer:

{2^(x-2)}*{x^2 - 1} = 3*2^13
So x-2=13, then x=15 is the correct answer.
Re: GMAT Prep Exponents   [#permalink] 10 May 2008, 22:21
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# Anyone know how to do this

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