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# as if AP wasn't enough

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Manager
Joined: 06 Jul 2007
Posts: 57

Kudos [?]: 27 [0], given: 0

as if AP wasn't enough [#permalink]

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19 Sep 2007, 12:58
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Hi, finally I planned to go beyond Manhattan and Kaplan's AP theory, I found some material in this forum itself. Having come from non-math background, I got intimidated by Geometrical sequence and ratio and b-l-ah b-l-a-h. Plz tell me if we really need to go into that stuff for GMAT? I remember I had seen some problems discussed here where some guys used these terms, which are all Greek to me.

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VP
Joined: 08 Jun 2005
Posts: 1144

Kudos [?]: 246 [0], given: 0

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19 Sep 2007, 22:05
have fun:

http://www.gmatclub.com/forum/t47969

I think that you get A.P problems on the GMAT once in a blue moon. And even then you can manage without the A.P formula.

Kudos [?]: 246 [0], given: 0

Manager
Joined: 06 Jul 2007
Posts: 57

Kudos [?]: 27 [0], given: 0

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20 Sep 2007, 08:03
Once again , Thanks a lot , KillerSquirrel.
I got stuck with Q 1 as I was pretty confident with answer 16. Then saw this discussion -

bkk145 wrote:
For question#1, do you consider 1 as an option?
I imagine you should start from 4 since by definition, 1/3 is really no remainder. Shouldn't the answer be 16?

No - to me 1/3 is zero (0) with remainder 1, since "3 goes into 1 zero (0) times" leaving a remainder of 1, and 3*0+1 = 1

Goshh...I can't digest this even though you have explained it with 3*0+1 = 1. Do you mean if we ever come across such problems with remainder one we must consider 1?? cuz any number will have X*0+1 true. right???

Kudos [?]: 27 [0], given: 0

VP
Joined: 08 Jun 2005
Posts: 1144

Kudos [?]: 246 [0], given: 0

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20 Sep 2007, 09:14
somethingbetter wrote:
Once again , Thanks a lot , KillerSquirrel.
I got stuck with Q 1 as I was pretty confident with answer 16. Then saw this discussion -

bkk145 wrote:
For question#1, do you consider 1 as an option?
I imagine you should start from 4 since by definition, 1/3 is really no remainder. Shouldn't the answer be 16?

No - to me 1/3 is zero (0) with remainder 1, since "3 goes into 1 zero (0) times" leaving a remainder of 1, and 3*0+1 = 1

Goshh...I can't digest this even though you have explained it with 3*0+1 = 1. Do you mean if we ever come across such problems with remainder one we must consider 1?? cuz any number will have X*0+1 true. right???

Yes ! this is quite right !

3/2 = remainder 1 since 2*1+1 = 3

1/2 = remainder 1 since 2*0+1 = 1

Kudos [?]: 246 [0], given: 0

20 Sep 2007, 09:14
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