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As shown below, convex pentagon ABCDE has sides AB =3, BC = 4, CD = 6,

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Math Expert
Joined: 02 Sep 2009
Posts: 59561
As shown below, convex pentagon ABCDE has sides AB =3, BC = 4, CD = 6,  [#permalink]

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29 Mar 2019, 00:18
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Difficulty:

55% (hard)

Question Stats:

47% (02:28) correct 53% (02:34) wrong based on 15 sessions

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As shown below, convex pentagon ABCDE has sides AB =3, BC = 4, CD = 6, DE = 3, and EA = 7. The pentagon is originally positioned in the plane with vertex A at the origin and vertex B on the positive x-axis. The pentagon is then rolled clockwise to the right along the x-axis. Which side will touch the point x = 2009 on the x-axis?

(A) AB
(B) BC
(C) CD
(D) DE
(E) EA

Attachment:

fd6ac5c8a85c125cb27930bfe3c7aa4b9cd98e12.png [ 17.36 KiB | Viewed 327 times ]
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Re: As shown below, convex pentagon ABCDE has sides AB =3, BC = 4, CD = 6,  [#permalink]

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29 Mar 2019, 03:35
2
Bunuel wrote:

As shown below, convex pentagon ABCDE has sides AB =3, BC = 4, CD = 6, DE = 3, and EA = 7. The pentagon is originally positioned in the plane with vertex A at the origin and vertex B on the positive x-axis. The pentagon is then rolled clockwise to the right along the x-axis. Which side will touch the point x = 2009 on the x-axis?

(A) AB
(B) BC
(C) CD
(D) DE
(E) EA

Attachment:
fd6ac5c8a85c125cb27930bfe3c7aa4b9cd98e12.png

sum of 1 complete roll = 23
so for 2009 atleast 87 complete rools to be done 87*23 = 2001 ; left with 2009-2001 ; 8 more to go
so next AB=3 , BC= 4 , at CD roll will reach 2009
IMO C
Re: As shown below, convex pentagon ABCDE has sides AB =3, BC = 4, CD = 6,   [#permalink] 29 Mar 2019, 03:35
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