It is currently 28 Jun 2017, 09:29

# Live Now:

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Assistance needed, GMAT prep

Author Message
Intern
Joined: 07 Aug 2009
Posts: 5
Location: Accra, Ghana
Schools: Wharton, HBS, Kellog

### Show Tags

14 Sep 2009, 10:55
1
This post was
BOOKMARKED
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 100% (03:28) wrong based on 1 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

...attached are 4 questions from the GMAT prep, i got really beaten up by. Any assistance to would be very much appreciated
Attachments

File comment: prep questions
gmat prep questions.xls [173.5 KiB]

Senior Manager
Joined: 20 Mar 2008
Posts: 452
Re: Assistance needed, GMAT prep [#permalink]

### Show Tags

14 Sep 2009, 11:47
PGY001 wrote:
...attached are 4 questions from the GMAT prep, i got really beaten up by. Any assistance to would be very much appreciated

I will respond to the first two. I have seen the other two on this forums, so please do a search.

#7:

Given:
bdc = 2x.
Therefore, bda=180-2x
Therefore, abd = 180 - adb - bad = 180 - (180-2x) - x = x.
Now, bd = bc (since bdc = bcd = 2x.

Therefore, bc = 6. SUFF.

St. 2: x = 36.
No info any of the lengths. Insuff.

A.
Senior Manager
Joined: 20 Mar 2008
Posts: 452
Re: Assistance needed, GMAT prep [#permalink]

### Show Tags

14 Sep 2009, 11:51
#12:

Let x = the height of the triangle.

Therefore, x^2 = t^2 - (t/2)^2 (Pythagoras theorem.)
Therefore, x = t* 3^(1/2) / 2

Therefore, area = 1/2 * t * t* 3^(1/2) / 2 = t^2 * 3^(1/2) / 4.

Area of square = s^2.

Therefore, t^2 * 3^(1/2) / 4 = s^2

Solving, t:s = 2: 3^(1/4)
D
Intern
Joined: 07 Aug 2009
Posts: 5
Location: Accra, Ghana
Schools: Wharton, HBS, Kellog
Re: Assistance needed, GMAT prep [#permalink]

### Show Tags

15 Sep 2009, 14:01
cheers Gmat Tiger...i do appreciate this a lot
Intern
Joined: 07 Aug 2009
Posts: 5
Location: Accra, Ghana
Schools: Wharton, HBS, Kellog
Re: Assistance needed, GMAT prep [#permalink]

### Show Tags

15 Sep 2009, 14:04
cheers Gmat Tiger...very much appreciated
Re: Assistance needed, GMAT prep   [#permalink] 15 Sep 2009, 14:04
Display posts from previous: Sort by