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At a certain conference, 72% of the attendees registered at least two [#permalink]

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30 Jan 2011, 07:43

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85% (hard)

Question Stats:

50% (01:59) correct
50% (02:05) wrong based on 88 sessions

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At a certain conference, 72% of the attendees registered at least two weeks in advance and paid their conference fee in full. If 10% of the attendees who paid their conference fee in full did not register at least two weeks in advance, what percent of conference attendees registered at least two weeks in advance?

(A) 18.0% (B) 62.0% (C) 79.2% (D) 80.0% (E) 82.0%

hi I tried to use this using Venn Diagram and got A as the answer can some one explain this to me using Venn

Re: At a certain conference, 72% of the attendees registered at least two [#permalink]

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31 Jan 2011, 08:39

whats wrong with using Venn diagram here ? 1 more thing, , using the given data , we get 80% of the total attendees (as those who paid full fee ) , not the % of those who registered two weeks in advance .
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At a certain conference, 72% of the attendees registered at least two [#permalink]

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14 May 2011, 22:49

At a certain conference, 72% of the attendees registered at least two weeks in advance and paid their conference fee in full. If 10% of the attendees who paid their conference fee in full did not register at least two weeks in advance, what percent of conference attendees registered at least two weeks in advance?

Re: At a certain conference, 72% of the attendees registered at least two [#permalink]

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15 May 2011, 01:09

fanatico wrote:

At a certain conference, 72% of the attendees registered at least two weeks in advance and paid their conference fee in full. If 10% of the attendees who paid their conference fee in full did not register at least two weeks in advance, what percent of conference attendees registered at least two weeks in advance? (A) 18.0% (B) 62.0% (C) 79.2% (D) 80.0% (E) 82.0%

Looks like this question is not complete. The required percent cannot be determined with given data. The answer can range from 72% to 92%. Could you please confirm?
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Re: At a certain conference, 72% of the attendees registered at least two [#permalink]

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17 May 2011, 11:39

fluke wrote:

fanatico wrote:

At a certain conference, 72% of the attendees registered at least two weeks in advance and paid their conference fee in full. If 10% of the attendees who paid their conference fee in full did not register at least two weeks in advance, what percent of conference attendees registered at least two weeks in advance? (A) 18.0% (B) 62.0% (C) 79.2% (D) 80.0% (E) 82.0%

Looks like this question is not complete. The required percent cannot be determined with given data. The answer can range from 72% to 92%. Could you please confirm?

Exactly we dont have any bifurcation of people who did not pay the full fee (how many registered in 2 week advance and how many did not)

without knowing that we can't reach the desired answer that how many registered in 2 weeks advance it could be 72% +0% (minimum) to 72% + 20% (maximum)

please clarify
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At a certain conference, 72% of the attendees registered at [#permalink]

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17 Sep 2012, 00:34

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At a certain conference, 72% of the attendees registered at least two weeks in advance and paid their conference fee in full. If 10% of the attendees who paid their conference fee in full did not register at least two weeks in advance, what percent of conference attendees registered at least two weeks in advance?

(A) 18.0% (B) 62.0% (C) 79.2% (D) 80.0% (E) 82.0%

Last edited by Bunuel on 01 Jan 2013, 02:28, edited 1 time in total.

Re: At a certain conference, 72% of the attendees [#permalink]

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17 Sep 2012, 13:14

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saikarthikreddy wrote:

Option D.

Number of people who registered early and paid full amount /Total number of people who paid full amount. =(72/82)*100 =80.0 %

Can you explain more clearly? I still don't get it. The problem ask what percent of conference attendees registered at least two weeks in advance. I think the formula should be Number of people who registered at least two weeks in advance/Total number of attendees.
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Re: At a certain conference, 72% of the attendees [#permalink]

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08 Nov 2012, 15:47

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Refer to the table in the attachment: Let x= No. of members who have paid in Full 10 % members paid in full and did not register in advance = 0.1x 72 % registerd in advance and paid in full.

So if total No. of members = 100, then 72 members paid Full and registered in advance.

Hence total members who paid full amount = 0.1x + 72 =x 0.9x =72 Hence x = 80 i.e. 80 out of 100 or 80 %

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