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At a certain industrial manufacturer, an open tank contains 6% fluorin

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At a certain industrial manufacturer, an open tank contains 6% fluorin  [#permalink]

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New post 30 Jun 2018, 06:50
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At a certain industrial manufacturer, an open tank contains 6% fluorine dissolved in water. If the tank holds 1000 gallons, and 10 gallons of the total volume evaporate as water each day, what is the concentration of fluorine after 25 days

A. 4%
B. 6%
C. 8%
D. 10%
E. 15%
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Re: At a certain industrial manufacturer, an open tank contains 6% fluorin  [#permalink]

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New post 30 Jun 2018, 09:15
Quantity of fluorine - 6% of 1000= 60 gallons

10 gallons of water evaporate everyday
So in 25 days - 250 gallons of water evaporates
remaining quantity -1000-250=750
concentration of fluorine after 25 days - (60/750 )*100=8% Ans C

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Re: At a certain industrial manufacturer, an open tank contains 6% fluorin  [#permalink]

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New post 30 Jun 2018, 23:46
Given 1000 gallons of sol.
6% flourine = 60
Rest water = 940
Now 10 gallons per day of total sol evaporates as water tricky
10 gallons per day so in 25 days 25x10 =250 gallons evaporated
Solution left 1000-250=750
So flourine concern = 60/750 = 0.08 =8%
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Re: At a certain industrial manufacturer, an open tank contains 6% fluorin  [#permalink]

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New post 25 Jul 2018, 04:02
Hey guys, a little confused...why are we doing the last step? Didn't some of the 60 gallons of the fluorine evaporate as well? How do we get that? :/Antreev
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Re: At a certain industrial manufacturer, an open tank contains 6% fluorin  [#permalink]

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New post 25 Jul 2018, 04:23
hibobotamuss wrote:
Hey guys, a little confused...why are we doing the last step? Didn't some of the 60 gallons of the fluorine evaporate as well? How do we get that? :/Antreev


The question clearly mentions that water evaporates and not fluorine.

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Re: At a certain industrial manufacturer, an open tank contains 6% fluorin  [#permalink]

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New post 25 Jul 2018, 06:59
wishalsp333 wrote:
At a certain industrial manufacturer, an open tank contains 6% fluorine dissolved in water. If the tank holds 1000 gallons, and 10 gallons of the total volume evaporate as water each day, what is the concentration of fluorine after 25 days

A. 4%
B. 6%
C. 8%
D. 10%
E. 15%


Total Volume = 1000 Gallons ; Fluorine = 60 Gallons & Water = 940 Gallons

Each day 10 gallons evaporates, so in 25 days 250 Gallons of water evaporates and we are left with 690 gallons of water and 60 Gallons of Fluorine.

Thus after 25 days total Volume is 750 Gallons out of which Fluorine is 60 Gallons.

So, Concentration of fluorine after 25 days is \(\frac{60}{750}*100\) = 8% , Answer must be (C)
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Re: At a certain industrial manufacturer, an open tank contains 6% fluorin  [#permalink]

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New post 26 Jul 2018, 16:27
wishalsp333 wrote:
At a certain industrial manufacturer, an open tank contains 6% fluorine dissolved in water. If the tank holds 1000 gallons, and 10 gallons of the total volume evaporate as water each day, what is the concentration of fluorine after 25 days

A. 4%
B. 6%
C. 8%
D. 10%
E. 15%



At the beginning, there are 0.06 x 1000 = 60 gallons of fluorine. After 25 days there are 1000 - 10 x 25 = 1000 - 250 = 750 gallons of liquid left. Therefore, the concentration of fluorine after 25 days is:

60/750 = 6/75 = 2/25 = 8/100 = 8%

Answer: C
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Re: At a certain industrial manufacturer, an open tank contains 6% fluorin &nbs [#permalink] 26 Jul 2018, 16:27
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