At a certain stage of a soccer tournament, the score ratio : GMAT Problem Solving (PS)
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# At a certain stage of a soccer tournament, the score ratio

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At a certain stage of a soccer tournament, the score ratio [#permalink]

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01 Dec 2012, 05:28
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Difficulty:

75% (hard)

Question Stats:

70% (01:57) correct 30% (00:20) wrong based on 23 sessions

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At a certain stage of a soccer tournament, the score ratio of teams A, B and C was 3:4:5. Eventually, the score ratio of A to B has doubled while the score ratio of A to C has halved. If the final score of team C was 40, what was the final score of team B?

1)8
2)10
3)20
4)40
5)80

I tried this as below:

a:b:c = 3:4:5

a:b= 3:4

doubled:
a:b = 2* 3:4 = 3:2

halved
a:c = (1/2)*3:5 = 3:10

a:c/a:b = (3/10)/ (3/2) = 6/30

given c =40

substituting, we get b = 8.

Pls let me know the basic approach on this.
[Reveal] Spoiler: OA
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Re: Need help on this Ratio basics [#permalink]

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01 Dec 2012, 05:44
2
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manukumar wrote:
At a certain stage of a soccer tournament, the score ratio of teams A, B and C was 3:4:5. Eventually, the score ratio of A to B has doubled while the score ratio of A to C has halved. If the final score of team C was 40, what was the final score of team B?

1)8
2)10
3)20
4)40
5)80

I tried this as below:

a:b:c = 3:4:5

a:b= 3:4

doubled:
a:b = 2* 3:4 = 3:2

halved
a:c = (1/2)*3:5 = 3:10

a:c/a:b = (3/10)/ (3/2) = 6/30

given c =40

substituting, we get b = 8.

Pls let me know the basic approach on this.

A to B = 3 : 4

So, on doubling we get 6 : 4

A to C = 3 : 5

So, on halving we get 1.5 : 5 or 3 : 10 or 6 : 20

So final ratio = 6 : 4 : 20.

If 20x = 40

4x = 8

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Re: At a certain stage of a soccer tournament, the score ratio [#permalink]

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22 Mar 2016, 11:16
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17 Feb 2017, 10:02
At a certain stage of a soccer tournament, the score ratio of teams A, B and C was 3:4:5. Eventually, the score ratio of A to B has doubled while the score ratio of A to C has halved. If the final score of team C was 40, what was the final score of team B?

a) 8
b) 10
c) 20
d) 40
e) 80
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17 Feb 2017, 10:26
Ratio of A:B is originally 3:4. Then this ratio is doubled and we have $$\frac{3}{2}$$ * 2 = $$\frac{6}{4}$$
Ratio of A:C is originally 3:5. Then this ratio is halved so we have $$\frac{3}{5}$$ * $$\frac{1}{2}$$ = $$\frac{3}{10}$$.

In order to compare the two ratio we must express the common term (in this case A) in the same quantity. Thus we multiply the second ratio ($$\frac{3}{10}$$) for 2 and we get $$\frac{6}{20}$$

So now the new score ratio of team A, B and C is 6:4:20. If we divide the score of team C by the ratio for team C we get the multiplier (in this case is 2).
Finally by applying the multiplier to B we get 8.

Hope it is clear.
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Re: At a certain stage of a soccer tournament, the score ratio [#permalink]

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17 Feb 2017, 13:06
dnalost wrote:
At a certain stage of a soccer tournament, the score ratio of teams A, B and C was 3:4:5. Eventually, the score ratio of A to B has doubled while the score ratio of A to C has halved. If the final score of team C was 40, what was the final score of team B?

a) 8
b) 10
c) 20
d) 40
e) 80

Merging topics. Please refer to the discussion above.
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At a certain stage of a soccer tournament, the score ratio [#permalink]

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17 Feb 2017, 20:24

A : B : C Initially:
3 : 4 : 5

6 : 4 (ratio A:B is doubled )

3 : __ : 10 (ratio is A: C is halved)
6 : __ : 20

6 : 4 : 20 Finally,
12 : 8 : 40 (since C has to become 40)

Therefore, B = 8
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At a certain stage of a soccer tournament, the score ratio   [#permalink] 17 Feb 2017, 20:24
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