It is currently 18 Nov 2017, 22:09

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# At a certain state university last term, there were p

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:

### Hide Tags

Director
Joined: 09 Aug 2006
Posts: 521

Kudos [?]: 111 [0], given: 0

At a certain state university last term, there were p [#permalink]

### Show Tags

19 Jun 2007, 22:40
5
This post was
BOOKMARKED
00:00

Difficulty:

45% (medium)

Question Stats:

64% (01:36) correct 36% (01:33) wrong based on 202 sessions

### HideShow timer Statistics

At a certain state university last term, there were p students each of whom paid either the full tuition of x dollars or half the full tuition. What percent of the tuition paid by the p students last term was tuition from students who paid the full tuition?

(1) Of the p students, 20 percent paid the full tuition.
(2) The p students paid a total of $91.2 million for tuition last term. [Reveal] Spoiler: OA Kudos [?]: 111 [0], given: 0 GMAT Club Legend Joined: 07 Jul 2004 Posts: 5032 Kudos [?]: 452 [0], given: 0 Location: Singapore Re: At a certain state university last term, there were p [#permalink] ### Show Tags 20 Jun 2007, 01:00 St1: Total tuition paid = 0.2px + 0.2*0.5px = 0.3px full tuition = 0.2px We can find the %. Sufficient. St2: Useless. Ans A Kudos [?]: 452 [0], given: 0 Senior Manager Joined: 21 Jun 2006 Posts: 282 Kudos [?]: 144 [0], given: 0 Re: At a certain state university last term, there were p [#permalink] ### Show Tags 20 Jun 2007, 13:49 A is sufficient B is not as you don't know what the original amount of tution is. Kudos [?]: 144 [0], given: 0 Director Joined: 30 Nov 2006 Posts: 591 Kudos [?]: 318 [0], given: 0 Location: Kuwait Re: At a certain state university last term, there were p [#permalink] ### Show Tags 20 Jun 2007, 18:07 Obtained from the question, total tuition paid = AX + BX/2 where A is the number of those who paid the full tuition and B is the number of those who paid half the tuition. X is the total full tuition paid for each student A+B = P The question asks for: AX/[AX+0.5BX] = AX/X[A+0.5B] = A/[A+0.5B] (1) Of the p students, 20 percent paid the full tuition. -------------------------------------------------------------- A/P = A/[A+B] = 0.2 A = 0.2A+0.2B 0.8A = 0.2 B --> B = 4A A/[A+0.5B] = A/[A+0.5x4A] = A/3A = 1/3 statement 1 is sufficient (2) The p students paid a total of$91.2 million for tuition last term.
------------------------------------------------------------------------------
AX + BX/2 = 91.2

So ?

statement 2 is insufficient

Kudos [?]: 318 [0], given: 0

Math Forum Moderator
Joined: 20 Dec 2010
Posts: 1965

Kudos [?]: 2089 [1], given: 376

Re: At a certain state university last term, there were p [#permalink]

### Show Tags

17 Apr 2011, 13:05
1
KUDOS
Amit05 wrote:
At a certain state university last term, there were p students each of whom paid either the full tuition of x dollars or half the full tuition. What percent of the tuition paid by the p students last term was tuition from students who paid the full tuition?

(1) Of the p students, 20 percent paid the full tuition.
(2) The p students paid a total of $91.2 million for tuition last term. Let "k" students paid full tuition of "$x"

 Tuition paid in full($x) Tuition paid in half$(x/2) Total Number of students k p-k p Total Sum Received kx $$\frac{x}{2}(p-k)$$ $$kx+\frac{x}{2}(p-k)$$

Q: What percent of the tuition paid by the p students last term was tuition from students who paid the full tuition?

Tuition paid by "p" students $$=kx+\frac{x}{2}(p-k)$$
Tuition paid by "k" students $$=kx$$

Q: What is $$\frac{kx}{kx+\frac{x}{2}(p-k)}$$
OR, if you simplify,
What is $$\frac{2k}{p+k}?$$

(1) Of the p students, 20 percent paid the full tuition.

$$\frac{k}{p}=\frac{1}{5}$$
$$5k=p$$
Substitute it in the main equation:
$$\frac{2k}{p+k}=\frac{2k}{5k+k}=\frac{1}{3}=33\frac{1}{3}%$$

Sufficient.

(2) The p students paid a total of \$91.2 million for tuition last term.

$$kx+\frac{x}{2}(p-k)=91.2m$$
Even though we have the denominator for $$\frac{kx}{kx+\frac{x}{2}(p-k)}$$, we will not be able to find the value of the numerator "kx".
Not Sufficient.

Ans: "A"
_________________

Kudos [?]: 2089 [1], given: 376

TOEFL Forum Moderator
Joined: 16 Nov 2010
Posts: 1602

Kudos [?]: 600 [0], given: 40

Location: United States (IN)
Concentration: Strategy, Technology
Re: At a certain state university last term, there were p [#permalink]

### Show Tags

17 Apr 2011, 21:46
Let n pay the full tuition

Fees paid = nx + (p-n)x/2

So the question asks :

nx/{nx + (p-n)x/2} * 100 = ?

From (1) :

n = 0.2p, which is sufficient as the variables cancel froom Nominator and denominator

From(2)

nx + (p-n)x/2 = 91.2 * 10^6, which is not sufficient, as we don't know the break-up of nx and (p-n)x/2

_________________

Formula of Life -> Achievement/Potential = k * Happiness (where k is a constant)

GMAT Club Premium Membership - big benefits and savings

Kudos [?]: 600 [0], given: 40

Non-Human User
Joined: 09 Sep 2013
Posts: 15704

Kudos [?]: 282 [0], given: 0

Re: At a certain state university last term, there were p [#permalink]

### Show Tags

31 Jul 2014, 10:48
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Kudos [?]: 282 [0], given: 0

Intern
Joined: 31 Oct 2015
Posts: 37

Kudos [?]: 6 [0], given: 53

Re: At a certain state university last term, there were p [#permalink]

### Show Tags

26 Nov 2015, 21:56
What is the percentage of full tuition from total tuition:

Statement 1: 20% of students paid full tuition.

For every student that paid a full tuition of 1, 4 students paid a half tuition of 1/2. Total tuition would be 1 + 4*1/2 = 3. The percentage of full tuition from total tuition is 1 of 3 or 33.3' %.

Sufficient.

Statement 2: Total tuition 92.1 mil. No way to determine percentage of full tuition.

Insufficient

Kudos [?]: 6 [0], given: 53

Director
Joined: 24 Nov 2015
Posts: 586

Kudos [?]: 40 [0], given: 231

Location: United States (LA)
Re: At a certain state university last term, there were p [#permalink]

### Show Tags

12 Apr 2016, 13:27
Statement A is sufficient as it gives the direct answer
Statement Bis not sufficient as we don't have any information on tuition fees

Kudos [?]: 40 [0], given: 231

Re: At a certain state university last term, there were p   [#permalink] 12 Apr 2016, 13:27
Display posts from previous: Sort by

# At a certain state university last term, there were p

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.