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At a certain university, the ratio of undergraduate students with an a
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15 Sep 2018, 00:18
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At a certain university, the ratio of undergraduate students with an associate’s degree to those without an associate’s degree is 1:3. Additionally, the ratio of graduate students to undergraduate students is 1:5. If all students at the university are either undergraduate or graduate students, what is the ratio of undergraduates without an associate’s degree compared with the entire student body? A. 1:15 B. 1:5 C. 3:8 D. 5:8 E. 4:5
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Re: At a certain university, the ratio of undergraduate students with an a
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15 Sep 2018, 01:23
Graduates = \(G\) Undergraduates = \(UG\) UG With Associates Degree = \(UGA\) UG Without Associates Degree = \(UGWA\)
Given
\(\frac{UGA}{UGWA} = \frac{1}{3}\)
so, \(UGA=\frac{UGWA}{3}\) eq. 1
also given, \(\frac{G}{UG} = \frac{1}{5}\)
logically, \(UGA+UGWA = UG\)  eq.2
so, \(\frac{G}{UGA+UGWA} = \frac{1}{5}\)  eq.3
Let \(S = UG+G\) ...all students at the university are either undergraduate or graduate students...
so, \(G=SUG\)
we can rewrite eq.3 as
\(\frac{(SUG)}{(UGA+UGWA)} = \frac{1}{5}\)
from eq.2,
\(\frac{(SUGAUGWA)}{(UGA+UGWA)} = \frac{1}{5}\)
from eq. 1,
\(\frac{(S1.333UGWA)}{(1.333UGWA)}\) = \(\frac{1}{5}\)
Divide numerator and denominator by S and separate \(\frac{UGWA}{S}\) from the other terms to reach the answer.
\(\frac{UGWA}{S} = \frac{5}{8}\) harish1986 wrote: At a certain university, the ratio of undergraduate students with an associate’s degree to those without an associate’s degree is 1:3. Additionally, the ratio of graduate students to undergraduate students is 1:5. If all students at the university are either undergraduate or graduate students, what is the ratio of undergraduates without an associate’s degree compared with the entire student body?
A. 1:15 B. 1:5 C. 3:8 D. 5:8 E. 4:5
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Re: At a certain university, the ratio of undergraduate students with an a
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26 Oct 2018, 07:07
I am not able to get the answer.
Ratio of Graduate and Under Graduate= 1:5  1x + 5x= 6x Ratio of Degree Students and Without Degree= 1:3 (which is actually under Graduate, which is 5x of total) Therefore 1x+3x=4x (5x of total)
Solving by this the answer is coming different. PLease help



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At a certain university, the ratio of undergraduate students with an a
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Updated on: 27 Oct 2018, 10:29
UG = undergraduates G = graduates A = associates degree WA = without associates degree T = total
You can draw a table like this.
_____UG____G____T__ A.....15........... _________________ WA..45........... _________________ ..T...60.....12.....72
Sorry for the dots and lines, I can't post images or urls
For the number of undergraduates you can choose a number which is divisible by 4,6 and 5. So if a total number of undergraduates is 60, than the number of undergraduates with associates degree is 15 and the number of undergraduate students without associates degree is 45 (\(\frac{15}{45} = \frac{1}{3}\)). The ratio of graduates and undergraduates is 1/5 and from that you can calculate the number of graduates \(\frac{60}{5} = 12\). At this point you have the number of undergraduates without degree and the total number of students. The final result is \(\frac{45}{(60 + 12)} = \frac{5}{8}\)
Originally posted by shtepa on 26 Oct 2018, 11:30.
Last edited by shtepa on 27 Oct 2018, 10:29, edited 1 time in total.



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Re: At a certain university, the ratio of undergraduate students with an a
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27 Oct 2018, 10:11
shtepa wrote: UG = undergraduates G = graduates A = associates degree WA = without associates degree T = total
You can draw a table like this.
_____UG____G____T__ A.....15........... _________________ WA..45........... _________________ ..T...60.....12.....72
Sorry for the dots and lines, I can't post images or urls
For the number of Under graduates you can choose a number which is divisible by 4,6 and 5. So if a total number of Under graduates is 60, than the number of undergraduates with associates degree is 15 and the number of grad. students without associates degree is 45 (\(\frac{15}{45} = \frac{1}{3}\)). The ratio of graduates and undergraduates is 1/5 and from that you can calculate the number of graduates \(\frac{60}{5} = 12\). At this point you have the number of undergraduates without degree and the total number of students. The final result is \(\frac{45}{(60 + 12)} = \frac{5}{8}\) Thanks. It really helped.. i think you missed 'Under' as highlighted... Thanks s much



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At a certain university, the ratio of undergraduate students with an a
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18 Jan 2019, 14:59
Here's my answer AashiS :
Plugging values:
Undergraduates are divided into two groups:
Associate’s degree to those without an associate’s degree is 1:3
So x + 3x = 4x; Let the total be 120 because is div by 4.
Hence, 30 + 90 = 120......1)
Graduate students to undergraduate students is 1:5 = x + 5x = 6x.
... 1) x + 120 = 6x
x = 24
Finally, 24 + 120 = 144
Plugging the values:
90/144 = 5/8... 5 : 8.
D




At a certain university, the ratio of undergraduate students with an a
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18 Jan 2019, 14:59






